Answer:
A:
Multiple: 3 * 5 = 15
Add: 7 + the result of step No. 1 = 7 + 15 = 22
Divide: 4 / 2 = 2
Subtract: the result of step No. 2 - the result of step No. 3 = 22 - 2 = 20
Add: the result of step No. 4 + 3 = 20 + 3 = 23
B:
Add: 7 + 3 = 10
Multiple: the result of step No. 1 * 5 = 10 * 5 = 50
Divide: 4 / 2 = 2
Subtract: the result of step No. 2 - the result of step No. 3 = 50 - 2 = 48
Add: the result of step No. 4 + 3 = 48 + 3 = 51
20000=p(1+0.05/12)^12*9
Solve for p
P=20,000÷(1+0.05÷12)^(12×9)
P=12,764.49
Answer:
Step-by-step explanation:
(2n - 3)(5n + 6) = 2n*(5n + 6) -3*(5n +6)
=2n*5n + 2n*6 -3*5n + (-3)*6
=10n² + 12n - 15n - 18
= 10n² -3n - 18
Answer:
a) 3.6
b) 1.897
c)0.0273
d) 0.9727
Step-by-step explanation:
Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.
a)
The mean of a Poisson random variable X is μ.
mean=E(X)=μ=3.6.
b)
The standard deviation of a Poisson random variable X is √μ.
standard deviation=S.D(X)=√μ=√3.6=1.897.
c)
The probability for Poisson random variable X can be calculated as
P(X=x)=(e^-μ)(μ^x)/x!
where x=0,1,2,3,...
So,
P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!
P(no case of rabies)=P(X=0)=0.0273.
d)
P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)
P(at least one case of rabies)=1-0.0273=0.9727
Answer:
7, 7.1, √51, 7.2
Step-by-step explanation:
√51 is 7.14
