Check your work here:
1)7/8.
7/8=0.875 and 3/4=0.75
2)3/20.
3/20=0.15 and 12.5%=0.125
3)48.4
increase by 10% means you multiply 44 by 100%+10% or 110% to get 48.4
4)612
decrease by 10% means you multiply 680 by 100%-10% or 90% to get 612
5)36,36,60
132/(3+3+5)*3,132/(3+3+5)*3,132/(3+3+5)*5
6)9.6,22.4
32/10*3, 32/10*7
7)20
14/0.7
8)31.5
18/4*7
9)17/12
2/3=8/12, 3/4=9/12 8/12+9/12=17/12
10)15/4
5*3/4
11)8
2^2+2*2=4+4=8
12)0
(-2)^2+(-2)*2=4-4=0
13)3
3(x-3)=0,(x-3)=0,x=3
14)2/5 or 0.4
5x+1=3,5x=2,x=2/5
15)5n+2
The sequence difference is 5 and the first term is 7
16)20
6(3)+2=18+2=20
17)-5
4(-2)+3=-8+3=-5
18)1
the coefficient of x is 1
19)4pi or 12.56
area of a circle is r^2*pi=2^2*pi=4pi
20)14pi or 43.96
circumference of a circle=2r*pi=2*4*pi=14pi
Answer:
D. Brea lives the farthest from school
Step-by-step explanation:
The easiest way to go about this is to get them all to the same unit. Let's do meters :)
3 kilometers = 3,000 meters (Kai)
30,000 centimeters = 300 meters (Cal)
and then of course 30,000 meters is already in the correct unit (Brea)
Given all of this, you can easily tell that the answer is D
282 because if u multipy 94 into 3 u get 282 and to check 282 divided by 3 is 94
Answer: $5.54
Step-by-step explanation: 63 divided by 100 is 0.63, 0.63 x 8.8 is 5.544 and 5.544 rounded to the nearest cent is $5.54
Answer:
The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Step-by-step explanation:
We are given that
Standard deviation, 
ounces
We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.
Assume the bag weight distribution is bell-shaped
Therefore,
We know that
Using the value of z
Now,
Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
