Keely and Grayson played a board game. Keely scored

Which function results after applying the sequence of transformations to

Ad libitum [116K]

Answer:

The resulting function after the sequence of transformations is $f(x)=3(x+2)^5+1$

Step-by-step explanation:

Given a function f(x)

the function a*f(x) will be a vertical stretch of factor a, given a > 1
the function f(x) + b will be the translated function vertically up b units
the function f(x+c) will be horizontally translated function of the original by c units left

Remembering these points, we can apply the rules to $x^5$ .

Strech vertically by 3 would be $3x^5$
translate up 1 unit would be $3x^{5}+1$
translate left 2 units would make it $3(x+2)^5+1$

Hence the new function would be $3(x+2)^5+1$

8 0

3 years ago

Write the equation of the line based on the given information explain the answer in slope intercept form

Butoxors [25]

Answer:

y = 2/3 x - 3

Step-by-step explanation:

substitute the given slope and the coordinate into the slope-intercpet form:

y = mx + b to solve for b,

-1 = 2/3(3) + b

=> b = -3

y = 2/3 x - 3

7 0

3 years ago

Which equation can be used to solve for x in the parallelogram below

Alexus [3.1K]

I can’t see the image it’s very blurry

7 0

3 years ago

Read 2 more answers

What is equivalent to log 25<br> 125

nexus9112 [7]

Log25 (5•25) = 3 over 2 aka 3/5

5 0

4 years ago

The Nelson Company makes the machines that automatically dispense soft drinks into cups. Many national fast food chains such as

S_A_V [24]

Answer:

a) 0 .0228

b) 14.69 ounces

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 16 ounces

Standard Deviation, σ = 0.4 ounces

We are given that the distribution of volume of soft drink is a bell shaped distribution that is a normal distribution.

Volume of new cup = 16.8 ounces

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) new cup will overflow when filled by the automatic dispenser

P( x > 16.8)

$P( x > 16.8) = P( z > \displaystyle\frac{16.8 - 16}{0.4}) = P(z > 2)$

$= 1 - P(z \leq 2)$

Calculation the value from standard normal z table, we have,

$P(x > 16.8) = 1 - 0.9772 = 0.0228 = 2.28\%$

0.0228 is the probability that a new cup will overflow when filled by the automatic dispenser.

b) mean amount dispensed by the machine be set to satisfy this wish

We have to find the value of x such that the probability is 0.006

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{16.8 - \mu}{0.4})=0.006$

$= 1 -P( z \leq \displaystyle\frac{16.8 - \mu}{0.4})=0.006$

$=P( z \leq \displaystyle\frac{16.8 - \mu}{0.4})=0.994$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{16.8 - \mu}{0.4} = 2.512\\\\\mu = 14.688\\\mu \approx 14.69$

Thus, the mean amount dispensed should be set to approximately 14.69 ounces so that the probability that a new cup will overflow is 0.006

3 0

3 years ago