3 years ago

Math question could someone help me !

Mathematics

1 answer:

umka2103 [35]3 years ago

8 0

Answer:

Step-by-step explanation:

SInce 2 out of 5 of 100 support it, that means that 40 support. This means that 60 do NOT support it

You might be interested in

T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is

K(x)= $\frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}$

The given curve is y=7 $e^{x}$

${y}''=7e^{x}\\ {y}'=7e^{x}$

k(x)= $\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

${k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}$

For Maxima or Minima

${k(x)}'=0$

$7(e^x)(1+49e^{2x})(98e^{2x}-1)=0$

→ $e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0$

$e^{x}=0 , ∧ 1+49e^{2x}=0$ [not possible ∵there exists no value of x satisfying these equation]

→ $98e^{2x}-1=0$

Solving this we get

x= $-\frac{1}{2}\ln{98}$

As you will evaluate ${k(x})}''$ <0 at x= $-\frac{1}{2}\ln98$

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[ $-\frac{1}{2}\ln98$ ,1/√2]

k(x)= $\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

k(x)= $\frac{7}{\infty}$

k(x)=0

5 0

3 years ago

Find the least common denominator for these fractions.

Elenna [48]

Answer:

Step-by-step explanation:

7 0

2 years ago

Find the common difference of the arithmetic sequence 13, 16, 19,...13,16,19,...

VLD [36.1K]

Answer:

the common difference is plus 3

4 0

3 years ago

-6(12p-8n) Please help me with this distributive property question.

ASHA 777 [7]

Answer:

=48n−72p

Step-by-step explanation: Good luck

3 0

3 years ago

Read 2 more answers

a science fair poster is a rectangle 48 inches long and 24 inches wide what is the area of the poster in square feet

anzhelika [568]

Answer:

Area=B×H=48×24=1,152 inches^2

8 0

4 years ago

Read 2 more answers