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lara31 [8.8K]
3 years ago
7

I need help on number 8-15 I’ll give you brainliest

Mathematics
1 answer:
galben [10]3 years ago
3 0

Question 8

It should be D) $101.35

Question 9

It should be C) It will always be less then the divisor

Question 10

It should be A) \frac{17}{18}

Question 11

It should be C) 5 and 9

Question 12

It should be  C) y=9x-4

Question 13

It should be A) (0,1)

Question 14

It should be D) The water starts off cold and then gets hotter

Question 15

It should be D) 7.2

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Using 4, 16, 10, 24, and 25 create a problem in which the answer equals 1.  You may use operations more than once.
Anton [14]

24 - 10 - 25 +16 - 4 = 1

is one way of doing it.

8 0
3 years ago
Read 2 more answers
I will give branliest to the first person to answer!
lara31 [8.8K]

Answer:

1: 10x-5

2: 6.5w-3y

3: 15+3n

4: not sure

8 0
2 years ago
I need help? Can you please tell me
BaLLatris [955]

Answer:

whats the questun

Step-by-step explanation:

7 0
2 years ago
−7/8 −(−5/6) ​ in simplest form
svp [43]

Answer:

-1/24

Step-by-step explanation:

-7/8 - (-5/6)

Subtracting a negative is like adding

-7/8 + 5/6

Get a common denominator

-7/8 * 6/6    + 5/6 *8/8

-42/48 + 40/46

-2/48

-1/24

3 0
2 years ago
PQ is rotated 180 degrees clockwise about P. What are the coordinates of P' and Q'?
Salsk061 [2.6K]

The co ordinates of P' is (-7,-2) and Q' is (-16, -8)

<u><em>Explanation</em></u>

PQ is rotated 180 degrees clockwise about P. It means <u>P and P' are the same points</u>.

According to the graph, the coordinates of P is (-7, -2) and  Q is (2, 4)

When PQ is rotated 180 degrees clockwise about P, then <u>P or P' will be the mid-point of Q and Q' </u>

Suppose, the co ordinate of Q' is (x, y)

Now according to the mid-point formula, the coordinate of P or P' will be: (\frac{x+2}{2},\frac{y+4}{2}) , which is actually at (-7, -2)

Thus.....

\frac{x+2}{2}=-7\\ \\ x+2=-14\\ \\ x= -16\\ \\ and\\ \\ \frac{y+4}{2}= -2\\ \\ y+4= -4\\ \\ y= -8

So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)

6 0
2 years ago
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