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3 years ago

Which of these variables affect the kinetic energy of a body? Select all that apply.

1 answer:

5 0

Speed, mass, and acceleration. Acceleration affects the kinetic energy, due to it affecting speed; therefore, the more acceleration, the more of an increase/decrease in kinetic energy.

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A stone is dropped from rest from the top of a building. It takes Î”t = 2.2 s for it to reach the ground.

NeTakaya

Answer:

Value of magnitude of acceleration will be $9.8m/sec^2$

Explanation:

It is given that when a stone is dropped it takes 2.2 sec to reach the ground

(a) As the stone is dropped from the top of building

So its initial velocity $u_i$ will be 0 m /sec

(b) As the stone is free falling and there is no external force applied on it so its acceleration will be equal to acceleration due to gravity

So value of magnitude of acceleration will be equal to $9.8m/sec^2$

6 0

3 years ago

A 1.0-kilogram rubber ball traveling east at 4.0 meters per second hits a wall and bounces back toward the west at 2.0 meters pe

Mrrafil [7]

Answer:

8 J and 2 J

Explanation:

Given that,

Mass of the rubber ball, m = 1 kg

Initial speed of the rubber ball, u = 4 m/s (in east)

Final speed of the rubber ball, v = -2 m/s (in west)

We need to find the kinetic energy of the ball before it hits the wall, the kinetic energy of the ball after it bounces off the wall.

Initial kinetic energy,

$K_i=\dfrac{1}{2}mv^2\\\\K_i=\dfrac{1}{2}\times 1\times (4)^2\\\\K_i=8\ J$

Final kinetic energy,

$K_f=\dfrac{1}{2}mv^2\\\\K_f=\dfrac{1}{2}\times 1\times (2)^2\\\\K_f=2\ J$

So, the initial kinetic energy is 8 J and the final kinetic energy is 2 J.

8 0

3 years ago

1750 N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and

Arturiano [62]

The time delay between the arrival of the two pulses at the ceiling is 2.33 ms.

<h3>What is center of gravity?</h3>

Any object of mass is attracted towards another by point where whole mass is supposed to be concentrated is called center of gravity.

A 1750 N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and weighing 0.290 N.

The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached.

Taking moments about one end, to find the tension at other end.

Tb X L = WxL/3

here, W is the weight, L is the length of wire and Tb is the tension at point B.

So, Tb = W/3

and
Tb - Ta = W

here, Ta is the tension in end A.

Substitute the values, we get

Tb = 583.33N and Ta = 1166.66N

Velocity of end A, Va = (1166.66 x1.25 x 9.81/0.290 )^(1/2)

Va = 222 m/s

Velocity of end B, Vb = (583.33 x1.25 x 9.81/0.290 )^(1/2)

Va = 157 m/s

Time delay t is related with the velocities as

t = L/Vb - L/Va

Substitute the values, we get

t= 0.00233 s

t = 2.33 ms

Thus, time delay between the arrival of the two pulses at the ceiling is 2.33 ms.

Learn more about center of gravity.

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8 0

2 years ago

PSYW - Please Show Your Work

Ad libitum [116K]

Answer:

9.66E4 J

Explanation:

7 0

3 years ago

The curved section of a horizontal highway is a circular unbanked arc of radius 740m. If the coefficient of static friction betw

fiasKO [112]

Coefficient of static friction = tan(a) = 0.4
r = 740 m
g = 9.8 m/s²
$v \: = \: \sqrt{gr \tan( \alpha ) }$
v = √(9.8 × 740 × 0.4) m/s
v ≈ 53.85908 m/s

6 0

4 years ago

Read 2 more answers