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Soloha48 [4]
3 years ago
5

A stone is dropped from rest from the top of a building. It takes Δt = 2.2 s for it to reach the ground.

Physics
1 answer:
NeTakaya3 years ago
6 0

Answer:

Value of magnitude of acceleration will be 9.8m/sec^2

Explanation:

It is given that when a stone is dropped it takes 2.2 sec to reach the ground

(a) As the stone is dropped from the top of building

So its initial velocity u_i will be 0 m /sec

(b) As the stone is free falling and there is no external force applied on it so its acceleration will be equal to acceleration due to gravity

So value of magnitude of acceleration will be equal to 9.8m/sec^2

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