Professor Turner wrote the expression below on the chalkboard for his team at the Research Center. He asked the scientists there
1 answer:
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In the plane, we have
everywhere. So in the equation of the sphere, we have
which is a circle centered at (2, -10, 0) of radius 4.
In the plane, we have
, which gives
But any squared real quantity is positive, so there is no intersection between the sphere and this plane.
In the plane,
, so
which is a circle centered at (0, -10, 3) of radius .