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2 years ago

The vertex of f(x) is (2, - 3) . is the vertex of f(x) + 3

Mathematics

1 answer:

Irina18 [472]2 years ago

3 0

Answer:

D. (2 , 0)

Step-by-step explanation:

f(x) + d --> (x , y) -> (x , y+d)

(2 , -3) -> (2 , -3+3) -> (2 , 0)

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A 10-ft vertical post casts a 14-inch shadow at the same time a nearby cell phone tower cast a 119-ft shadow. How tall is the ce

Yakvenalex [24]

Answer:

The cellphone towers height is 1020 ft.

Step-by-step explanation:

This question is solved using proportions, by a rule of three.

A 10-ft post casts a 14-inch shadow.

Each feet has 12 inches, which means that a post with 10 feet will cast a 14/12 = 1.167 ft shadow. How tall is the cell-phone tower with a 119-feet shadow?

10 feet post - 1.167 ft shadow

x feet tower - 119 feet shadow

Applying cross multiplication:

$1.167x = 10*119$

$x = \frac{1190}{1.167}$

$x = 1020$

The cellphone towers height is 1020 ft.

8 0

2 years ago

What is the quotient?

yuradex [85]

Answer:

-1.58208955224

Step-by-step explanation:

DO THE MATH

5 0

2 years ago

A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben

juin [17]

Answer:

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.