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sashaice [31]
2 years ago
6

Write it as a single logarithm

Mathematics
1 answer:
WINSTONCH [101]2 years ago
6 0

Answer:

0

Step-by-step explanation:

log b (3-3)

log b (0)

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You want to enlarge a 4 x 5 inch photo to fit into a 1 inch wide frame
skelet666 [1.2K]

The 4•x by 5•x inner dimensions of the 53 inches outer perimeter picture frame, the 1 inch wide frame and the 4 × 5 inch picture to be enlarged, gives;

a. The outer perimeter equation is presented as follows;

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b. The scale factor required for the enlargement of the picture is 2.5

<h3>Which method can be used to write the equation and find the scale factor?</h3>

The dimensions of the photo = 4 × 5 inch

Width of the frame = 1 inch

Outer perimeter of the frame = 53 inches

The width of the inside of the picture frame = 4•x

The height of the inside of the picture frame = 5•x

a. The equation for the outer perimeter of the picture frame is therefore;

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Which gives;

2 × (4•x + 2) + 2 × (5•x + 2) = 53

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A simplified equation for the outer perimeter of the picture frame is therefore;

  • 18•x + 8 = 53

b. Solving the above equation, we have;

18•x + 8 = 53

18•x = 53 - 8 = 45

18•x = 45

Therefore;

x = 45 ÷ 18 = 2.5

x = 2.5

The width and height of the picture frame are therefore;

Width = 4•x = 4 × 2.5 = 10

Height = 5•x = 5 × 2.5 = 12.5

Which gives;

Width = 10 inches

Height = 12.5 inches

The enlargement factor, sf, is given by the ratio of a side of the picture frame to a side of the picture as follows;

sf = 12.5/5 = 2.5

  • The factor by which to enlarge the picture frame is 2.5

Learn more about linear scale factors here:

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asambeis [7]
Hello,

Answer B

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