Hydrogen may have a +1 or -1 charge.

An unknown solution has a pH of 7. How would you classify this solution?

xenn [34]

Solution with a ph of 7 Is neutral

7 0

3 years ago

Cierto elemento presenta dos isótopos cuyos números de masa suman 110 y cuyos números de neutrones suman 58 ¿Cuál es el número a

Anettt [7]

Answer:

El número atómico de cada uno de los átomos es 26

Explanation:

El número de masa es la suma de las masas del protón y el neutrón de un átomo.

El número atómico es el número de protones en el átomo.

Los parámetros dados son;

La suma del número másico de ambos átomos = 110

La suma de los neutrones = 58

Por lo tanto, sea el número de protones y neutrones en un isótopo = P₁ y N₁ y el número de protones y neutrones en el otro isótopo = P₂ y N₂

Tenemos;

P₁ + N₁ + P₂ + N₂ = 110

N₁ + N₂ = 58

Por lo tanto;

P₁ + P₂ = 110 - (N₁ + N₂)

P₁ + P₂ = 110 - 58 = 52

Dado que los isótopos son del mismo elemento, sus protones serán iguales, por lo tanto;

P₁ = P₂

P₁ + P₂ = P₁ + P₁ = 2 × P₁

P₁ + P₂ = 52

2 × P₁ = 52

P₁ = 52/2 = 26 = P₂

El número atómico de ambos átomos es el número de protones en el átomo que es 26.

El número atómico del elemento del átomo es 26

6 0

3 years ago

Which of the following explanations accounts for the fact that the ion-solvent interaction is greater for Li than for K

OLEGan [10]

Li+ has a smaller ionic radius than K+

and smaller molecules have more collisions/interactions between each other

<h3>What is ion-solvent interaction ?</h3>

In the case of ion-solvent interactions, the state in which the interac-tions exist is an obvious one; it is the situation in which ions are inside the solvent.

Ions are charged particles, and charges interact with other charges. So there will also be ion-ion, as well as ion-solvent, interactions in the solution.

In the process of solvation, ions are surrounded by a concentric shell of solvent. Solvation is the process of reorganizing solvent and solute molecules into solvation complexes.

Learn more about Ion-solvent interaction here:

brainly.com/question/21307101

#SPJ4

6 0

2 years ago

Why might people add a base to an acidic lake?

spayn [35]

Answer:

To decrease the algae

Explanation:

Acid lakes have more algae than other lakes

6 0

3 years ago

A compound is composed of C, H and O. A 1.621 g sample of this compound was combusted, producing 1.902 g of water and 3.095 g of

vlada-n [284]

Answer: The molecular of the compound is, $C_2H_3O$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=3.095g$

Mass of $H_2O=1.902g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in $3.095g$ of carbon dioxide, $\frac{12}{44}\times 3.095=0.844g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in $1.902g$ of water, $\frac{2}{18}\times 1.092=0.121g$ of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = $(1.621)-[(0.844)+(0.121)]=0.656g$

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.844g}{12g/mole}=0.0703moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.121g}{1g/mole}=0.121moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.656g}{16g/mole}=0.041moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is $0.041$ moles.

For Carbon = $\frac{0.0703}{0.041}=1.71\approx 2$

For Hydrogen = $\frac{0.121}{0.041}=2.95\approx 3$

For Oxygen = $\frac{0.041}{0.041}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 2 : 3 : 1

Hence, the empirical formula for the given compound is $C_2H_3O_1=C_2H_3O$

The empirical formula weight = 2(12) + 3(1) + 1(16) = 43 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

$n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}$

$n=\frac{46.06}{43}=1$

Molecular formula = $(C_2H_3O_1)_n=(C_2H_3O_1)_1=C_2H_3O$

Therefore, the molecular of the compound is, $C_2H_3O$

6 0

3 years ago