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labwork [276]
3 years ago
15

6th Grade Science question on Mass, Volume, and Density!! I've tried and tried and I can't figure it out!​

Chemistry
1 answer:
Sonbull [250]3 years ago
8 0
If you want to find density, do mass divided by the volume and there’s your answer!
You might be interested in
How many grams of precipitate will be formed when 20.5 mL of 0.800 M
Anton [14]

Answer:

There will be formed 1.84 grams of precipitate (NaNO3)

Explanation:

<u>Step 1</u>: The balanced equation

CO(NO3)2 (aq) + 2 NaOH (aq) → CO(OH)2 (s) + 2 NaNO3 (aq)

<u>Step 2:</u> Data given

Volume of 0.800 M  CO(NO3)2 = 20.5 mL = 0.0205 L

Volume of 0.800 M NaOH = 27.0 mL = 0.027 L

Molar mass of NaNO3 = 84.99 g/mol

<u>Step 3:</u> Calculate moles of CO(NO3)2

Moles CO(NO3)2  = Molarity * volume

Moles CO(NO3)2  = 0.800 M * 0.0205

Moles CO(NO3)2 = 0.0164 moles

Step 4: Calculate moles NaOH

moles of NaOH = 0.800 M * 0.027 L

moles NaOH = 0.0216 moles

Step 5: Calculate limiting reactant

For 1 mole CO(NO3)2 consumed, we need 2 moles of NaOH to produce 1 mole of CO(OH)2 and 2 moles of NaNO3

NaOH is the limiting reactant. It will completely be consumed.

CO(NO3)2 is in excess. There willbe 0.0216 / 2 = 0.0108 moles of CO(NO3)2 consumed. There will remain 0.0164 - 0.0108 = 0.0056 moles of CO(OH)2

Step  6: Calculate moles of NaNO3

For 2 moles of NaOH consumed, we have 2 moles of NaNO3

For 0.0216 moles of NaOH, we have 0.0216 moles of NaNO3

Step 7: Calculate mass of NaNO3

mass of NaNO3 = moles of NaNO3 * Molar mass of NaNO3

mass of NaNO3 = 0.0216 moles * 84.99 g/mol = 1.84 grams

There will be formed 1.84 grams of precipitate (NaNO3)

5 0
3 years ago
A solution at ph 10 contains __________ than the same amount of solution at ph 8.
Sindrei [870]

100 times less H+

A solution at ph 10 contains<u> </u><u>100 times less H+</u> than the same amount of solution at ph 8.

<h3>The pH scale: How does it function?</h3>
  • The pH scale determines how acidic or basic water is.
  • The range is 0 to 14, with 7 representing neutrality.
  • Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7.
  • In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.

<h3>How does the pH change when two acids are combined?</h3>
  • An acid's strength increases with the quantity of hydrogen ions it releases.
  • The pH of the strong acids is between 1 and 2.
  • We may observe that there is no response when two acids of the same strength are combined.
  • It's because the end product will be neutral and the pH won't change.

<h3>How is pH value determined?</h3>

There are two ways to measure pH:

  • colorimetrically with indicator fluids or sheets
  • electrochemically with electrodes and a millivoltmeter for greater accuracy (pH meter).

To learn more about pH visit:

brainly.com/question/491373

#SPJ4

8 0
2 years ago
With reference to He-4 (or the diagram), explain the term isotopes.
boyakko [2]

Answer:

Isotopes are basically atoms of an element that have an unequal number of neutrons and protons. Of course the proton number remains the same, but the neutron number either decreases or increases, which leads to an overall change in mass. However, no chemical properties of the atom/element are changed as the electrons are the same number and do not react. In regards to Helium 4, the original number of neutrons in Helium is 2, and protons 2 as well. We see an equal number of neutrons and protons, hence an unchanged mass, and the element is <em>not</em> an isotope.

6 0
3 years ago
A salt bridge is used to provide electrons a path to flow from the electrode of one half-cell to another. TRUE FALSE
kicyunya [14]
It is false. The salt bridge is not a path for electrons, but a path for ions to flow from one half-cell to another. It help to balance the charge between the oxidation and reduction vessels.
8 0
3 years ago
A compound is found to have 55.7% hafnium+and+44.3%+chlorine.+what+is+the+empirical+formula?
uranmaximum [27]

The empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

<h3>How to calculate empirical formula?</h3>

The empirical formula of a compound is a notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.

The empirical formula of the given compound can be calculated as follows:

  • Hafnium = 55.7% = 55.7g
  • Chlorine = 44.3% = 44.3g

First, we convert mass values to moles by dividing by the molar mass of each element

  • Hafnium = 55.7g ÷ 178.49g/mol = 0.312mol
  • Chlorine = 44.3g ÷ 35.5g/mol = 1.25mol

Next, we divide each mole value by the smallest

  • Hafnium = 0.312 ÷ 0.312 = 1
  • Chlorine = 1.25 ÷ 0.312 = 4

Therefore, the empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

Learn more about empirical formula at: brainly.com/question/14044066

#SPJ1

7 0
1 year ago
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