Answer:
The answer is C=6p3 + 29p2 + 22p – 21
Step-by-step explanation:
To calculate the product, we need to multiply each member of each multiplier:
(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3
= 6p³ + 8p² - 6p + 21p² + 28p - 21
= 6p³ + 8p² + 21p² + 28p - 6p -21
= 6p³ + 29p² + 22p - 21
Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21
If the teacher isn't putting the names back in the hat then it would be 1/21 if she is then 1/23
Answer: 22
Step-by-step explanation:
I got it right on khan academy
68 because it is a perpendicular bisector we can assume that the angles full length is 90 degrees meaning you can just do 90-22=68
Answer:
3/2 < x < 2
Step-by-step explanation:
We assume the problem is ...
[tek]\dfrac{1}{x-2}<-2[/tex]
This will not be true for x-2 > 0 because that would make the left side positive. So, we must have x < 2, which makes the denominator negative. Multiplying by (x-2), we get ...
1 > -2(x -2)
1 > -2x +4
2x > 3 . . . . . . add 2x-1
x > 3/2
From above, we also have x < 2, so the solution set is ...
3/2 < x < 2
