<span>(r9 - s10) • (r18 + r9s10 + s20)</span>
There are four numbers of 3-coin combinations if we can choose from nickels, dimes, quarters, and half-dollars.
<h3>How to solve probability combinations?</h3>
The coins to select from are nickels, dimes, quarters, and half-dollars;
Thus;
Coins (n) = 4
The number of coin to select is:
Coin (r) = 3
The coin combination is then calculated using:
Combination = ⁴C₃
Apply the combination formula, we have;
Combination = 4
Thus, there are four number 3-coin combinations if we can choose from nickels, dimes, quarters, and half-dollars.
Read more about combinations at; brainly.com/question/4658834
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Answer:
124
Step-by-step explanation:
360 - (90+146) = 124
Answer:
a) 2.9%
b) Option B is correct.
The prisoners must be independent with regard to recidivism.
Step-by-step explanation:
Probability that one prisoner goes back to prison = 17% = 0.17
a) The probability that two prisoners released both go back to prison = 0.17 × 0.17 = 0.0289 = 2.89% = 2.9% to 1 d.p
b) The only assumption taken during the calculation is that probability of one of the prisoners going back to prison has no effect whatsoever in the probability that another prisoner goes back to prison. That is the probability that theses two events occur are totally independent of each other.
If they weren't, we wouldn't be able to use 0.17 as the probability that the other prisoner goes back to prison too.
