Question

If an airplane descends 15 feet every 1.45 seconds, how far would the airplane travel in three and a half minutes? The equation is y=-40x+58

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}$

Here we go ~

The air plane descends 15 feels every 1.45 seconds, so it's unit rate is :

$\qquad \sf \dashrightarrow \: \dfrac{15}{1.45} \: \: ft / sec$

Now we have to calculate the descent in 3.5 minutes ~

$\qquad \sf \dashrightarrow \: \dfrac{15}{1.45} \: \: \times 3.5 \times 60$

$\qquad \sf \dashrightarrow \: 2172.41 \: \: ft$

So, the airplane descends 2172.41 feels in three and a half minutes ~