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dmitriy555 [2]
3 years ago
12

Find the next three terms in the numbers sequence 5,11,24,51,_,_,_.​

Mathematics
1 answer:
vfiekz [6]3 years ago
6 0

Answer:

106, 217, 440

Step-by-step explanation:

the pattern is that the number is multiplied by 2 and then added x to it. x increases in value by 1 every number. 5*2+1=11. 11*2+2=24. 24*2+3=51. so,

51*2+4=106

106*2+5=217

217*2+6=440

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kvv77 [185]

Answer: Yes

Step-by-step explanation:

So a coordinate pair is always set up (x,y) so you plug the x term in the coordinate pair into the x in the equation and the y term in for the y. 3×2 + 2×-1. Multiply them together and you end up with 4.

3 0
3 years ago
Find the value of Y!!!!<br><br> A. 4°<br> B. 24°<br> C. 65°<br> D. 155°
nadya68 [22]

Answer:

155

Step-by-step explanation:

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5 0
4 years ago
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In the figure what is the length of the tangent from the external point D to point B point point
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4 years ago
Ronald spins a spinner that has 10 sections numbered from 1 to 10. What is the probability that the spinner lands on a prime num
vladimir1956 [14]
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5 0
3 years ago
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Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

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8+\ln9=C

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8 0
3 years ago
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