Answer:
eekk im not shure sorry but it might be 8156 i no no
Step-by-step explanation:
Let's solve your inequality step-by-step.
<span><span><span>5x</span>+3</span>><span><span>4x</span>+7
</span></span>Step 1: Subtract 4x from both sides.
<span><span><span><span>5x</span>+3</span>−<span>4x</span></span>><span><span><span>4x</span>+7</span>−<span>4x
</span></span></span><span><span>x+3</span>>7
</span>Step 2: Subtract 3 from both sides.
<span><span><span>x+3</span>−3</span>><span>7−3
</span></span><span>x>4
</span>Answer:
<span>x><span>4</span></span>
The inverse of the function x^7 is x^-7 and it is also a function.
An inverse function or an anti function is defined as a function, which can reverse into another function.
A standard method to find inverse of a function is to set y=f(x)
let y= f(x)=x^7
thus
=x
thus
(y)=![\sqrt[7]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7By%7D)
thus ![f^{-1} (x)=\sqrt[7]{x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%20%28x%29%3D%5Csqrt%5B7%5D%7Bx%7D)
(To verify this if a function is inverse or not we are required to check for the identity)
f(
(x))=
(f(x))=x
Therefore, The inverse of the function x^7 is x^-7 and it is also a function.
For further reference:
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Answer:
The value of 4 is an input of the function
Step-by-step explanation:
Let
x -----> the independent variable or input value
y ----> the dependent variable or output value
we know that
Looking at the graph
The domain (input values) of the linear function is equal to the interval
[1,∞)

All real numbers greater than or equal to 1
The range (output values) of the linear function is equal to the interval
(-∞,3]

All real numbers less than or equal to 3
therefore
The value of 4 is an input of the function
Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere

The differential of V with respect to r is:

dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³