Answer: Choice A
Work Shown:
What are the missing parts that correctly complete the proof? Given: Point A is on the perpendicular bisector of segment P Q. Pr
ove: Point A is equidistant from the endpoints of segment P Q. Image: A horizontal line segment P Q. A midpoint is drawn on segment P Q labeled as X. A vertical line X A is drawn. A is above the horizontal line. The angle A X Q is labeled a right angle. The line segments P X and Q X are labeled with a single tick mark. A dotted line is used to connect point P with point A. Another dotted line is used to connect point Q with point A. Drag the answers into the boxes to correctly complete the proof. Statement Reason 1. Point A is on the perpendicular bisector of PQ¯¯¯¯¯. Given 2. PX¯¯¯¯¯≅QX¯¯¯¯¯¯ Response area 3. ∠AXP and ∠AXQ are right angles. Response area 4. Response area All right angles are congruent. 5. AX¯¯¯¯¯≅AX¯¯¯¯¯ Reflexive Property of Congruence 6. △AXP≅△AXQ Response area 7. AP¯¯¯¯¯≅AQ¯¯¯¯¯ Response area 8. Point A is equidistant from the endpoints of PQ¯¯¯¯¯. Definition of equidistant Look below me
1 answer:
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Answer:
k = 4 units
Step-by-step explanation:
Using Pythagoras' identity on the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
k² + 7.5² = 8.5²
k² + 56.25 = 72.25 ( subtract 56.25 from both sides )
k² = 16 ( take the square root of both sides )
k = = 4