2 years ago

Need help with 13 14 and 15

Mathematics

1 answer:

ad-work [718]2 years ago

6 0

Answer:

njbvi3brfjkncdoewkmdrfrj

Step-by-step explanation:

gagagagagaggag

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PLEASE HELP QUICK, I need to know the answer.

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The equivalent expression is $7^{2}$ .

We have the following expression -

$\frac{7^{-3} }{7^{-5} }$

We have to find its equivalent value.

<h3>What is the equivalent expression of the following expression-</h3>

$f(x, y) =\frac{A^{x} }{A^{y} }$

In order to divide two exponents with same base, we use the 'Quotient property of exponents.

The equivalent expression can be written as -

f(x, y) = $A^{x} A^{-y} = A^{x-y}$

In the question given we have -

$\frac{7^{-3} }{7^{-5} }$

Using the property discussed above -

$7^{-3}\;7^{5}$ = $7^{-3+5}$ = $7^{2}$

Hence, the equivalent expression is $7^{2}$ .

To solve more questions on exponents, visit the link below -

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Find the 7th term of the geometric sequence -5, 15, 45, 135, 405,...

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Answer:

1,215

Step-by-step explanation:

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First subtract the 7 from both sides and that would equal 2x+9=2x then subtract 2x and the answer is 9

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