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3 years ago

5

Help me plsssss I have more but this one first

2 answers:

Alexeev081 [22]3 years ago

4 0

Answer:

$1205.76 \: \: {units}^{3}$

Step-by-step explanation:

$v = \pi {r}^{2} h \\ = 3.14 \times {8}^{2} \times 6 \\ = 3.14 \times 64 \times 6 \\ = 1205.76 \: \: {units}^{3}$

Hope this helps you

<em>Can</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>the</em><em> </em><em>brainliest</em><em> </em><em>please</em><em>?</em>

Kisachek [45]3 years ago

3 0

Answer:

below is te answer

Step-by-step explanation:

1205.76 is the answer i took this test last year i still had the paper

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Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

3 years ago

Harry cycles 8 kilometres in 30 minutes.<br> Calculate his average speed, in km/h

Lerok [7]

8 km / 0.5 hr
= 16 km/h

4 0

3 years ago

Read 2 more answers

What is the value of n<br><br> 2.3x10^9 = (1x10^3) (2.3x10^n)

n200080 [17]

Here's one shortcut:

2.3×10^9=1000(2.3×10^6) because your adding 3 more zeros to 2300000

6 0

3 years ago

HELP PLEASE!!! ILL GIVE BRAINLIEST!!!!!

Semenov [28]

Answer:

h= -128t

Step-by-step explanation:

- 16t+128t

-256t + 128

3 0

3 years ago

The average marks of the first 10 students are 17 and that of the next 15 students is 18. find the mean of 25 students?

Ray Of Light [21]

Answer:

The mean of 25 students is 17.6

Step-by-step explanation:

The formula of the mean (average) is mean (average) = $\frac{S}{N}$ , where S is the sum of the data, and N is the number of the data

∵ The average marks of the first 10 students are 17

- That means the mean is 17 and the number of students is 10

∴ Average = 17

∴ N = 10

∵ Average = $\frac{S}{N}$

- Substitute average by 17 and N by 10

∴ 17 = $\frac{S}{10}$

- Multiply both sides by 10

∴ 170 = S

∴ The sum of the marks of the first 10 students is 170

∵ The average of the next 15 students is 18

∴ Average = 18

∴ N = 15

- Substitute average by 18 and N by 15

∴ 18 = $\frac{S}{15}$

- Multiply both sides by 15

∴ 270 = S

∴ The sum of the marks of the next 15 students is 270

Now to find the mean of 25 students and the two sums and divide the answer by 25

∵ S = 170 + 270

∴ S = 440

∵ N = 25

∴ Mean = $\frac{440}{25}$

∴ Mean = 17.6

The mean of 25 students is 17.6

3 0

3 years ago