Help me plsssss I have more but this one first

Mathematics

2 answers:

Alexeev081 [22]3 years ago

4 0

Answer:

$1205.76 \: \: {units}^{3}$

Step-by-step explanation:

$v = \pi {r}^{2} h \\ = 3.14 \times {8}^{2} \times 6 \\ = 3.14 \times 64 \times 6 \\ = 1205.76 \: \: {units}^{3}$

Hope this helps you

Can I have the brainliest please?

Kisachek [45]3 years ago

3 0

Answer:

below is te answer

Step-by-step explanation:

1205.76 is the answer i took this test last year i still had the paper

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marysya [2.9K]

The first option is correct.

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3 years ago

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Hitman42 [59]

By using algebra properties and trigonometric formulas we find that the trigonometric expression $\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ is equivalent to the trigonometric expression $\frac{2\cdot \tan x}{\cos x}$ .

<h3>How to prove a trigonometric equivalence by algebraic and trigonometric procedures</h3>

In this question we have trigonometric expression whose equivalence to another expression has to be proved by using algebra properties and trigonometric formulas, including the fundamental trigonometric formula, that is, cos² x + sin² x = 1. Now we present in detail all steps to prove the equivalence:

$\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ Given.

$\frac{1 + \sin x - 1 + \sin x}{1 - \sin^{2}x}$ Subtraction between fractions with different denominator / (- 1) · a = - a.

$\frac{2\cdot \sin x}{\cos^{2}x}$ Definitions of addition and subtraction / Fundamental trigonometric formula (cos² x + sin² x = 1)

$\frac{2\cdot \tan x}{\cos x}$ Definition of tangent / Result

By using algebra properties and trigonometric formulas we conclude that the trigonometric expression $\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ is equal to the trigonometric expression $\frac{2\cdot \tan x}{\cos x}$ . Hence, the former expression is equivalent to the latter one.

To learn more on trigonometric equations: brainly.com/question/10083069

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2 years ago

F(x)= x^2 What is f(x) + f(x) + f(x)?

Alik [6]

Answer:

$3x^2$