Answer:
The objective function in terms of one number, x is
S(x) = 4x + (12/x)
The values of x and y that minimum the sum are √3 and 4√3 respectively.
Step-by-step explanation:
Two positive numbers, x and y
x × y = 12
xy = 12
S(x,y) = 4x + y
We plan to minimize the sum subject to the constraint (xy = 12)
We can make y the subject of formula in the constraint equation
y = (12/x)
Substituting into the objective function,
S(x,y) = 4x + y
S(x) = 4x + (12/x)
We can then find the minimum.
At minimum point, (dS/dx) = 0 and (d²S/dx²) > 0
(dS/dx) = 4 - (12/x²) = 0
4 - (12/x²) = 0
(12/x²) = 4
4x² = 12
x = √3
y = 12/√3 = 4√3
To just check if this point is truly a minimum
(d²S/dx²) = (24/x³) = (8/√3) > 0 (minimum point)
Answer:
i
Step-by-step explanation:
I am not sure check with others
Answer:
B.
Step-by-step explanation:
First, let's start from the parent function. The parent function is:
The possible transformations are so:
,
where a is the vertical stretch, b is the horizontal stretch, c is the horizontal shift and d is the vertical shift.
From the given equation, we can see that a=1 (so no change), b=3, c=-3 (<em>negative </em>3), and d=3.
Thus, this is a horizontal stretch by a factor of 3, a shift of 3 to the <em>left </em>(because it's negative), and a vertical shift of 3 upwards (because it's positive).
Answer:
x = - 45
Step-by-step explanation:
x+23(-23)=−22 (-23)First subtract 23 from both sides
x = - 45
