3 years ago

Write each product using an exponent. 2 × 2 × 2 × 2 × 2 × 2 × 2

Mathematics

2 answers:

UkoKoshka [18]3 years ago

5 0

Answer:

2^7 is ypur answer

lutik1710 [3]3 years ago

3 0

2^7 is the answer to you’re question

You might be interested in

Y = -2x + 2 y = 5x + 9

WITCHER [35]

X=-1 y=4 hope it helps

8 0

3 years ago

What is 5/9*2 4/ equal

Kobotan [32]

The answer is 1.11111

6 0

3 years ago

Write an equivalent expression for 7 + 5 k minus 2 minus 3 k + n. Which statements are true about the steps for writing the equi

Nataly [62]

Answer:

1. Combine the constant terms by adding 7 and –2.

4. Combine the like variable terms by adding the coefficients

5. 5 k and negative 3 k are like variable terms

6.The constants 7 and –2 are like terms.

7. The equivalent expression is 5 + 2 k + n.

5 0

3 years ago

Plz help me i did it but messed up some ware plz help . 5x5=4x5+9=

Lyrx [107]

Answer: 25=29

Step-by-step explanation:5x5=25

4x5+9=29

5 0

3 years ago

Read 2 more answers

The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given

slavikrds [6]

Answer:

a) $\frac{dm}{dt} = -k\cdot m$ , b) $m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ , c) $m(t) = 10\cdot e^{-\frac{t}{2438.155} }$ , d) $m(300) \approx 8.842\,g$

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

$\frac{dm}{dt} = -k\cdot m$

b) The general solution is found after separating variables and integrating each sides:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $\tau$ is the time constant and $k = \frac{1}{\tau}$

c) The time constant is:

$\tau = \frac{1690\,yr}{\ln 2}$

$\tau = 2438.155\,yr$

The particular solution of the differential equation is:

$m(t) = 10\cdot e^{-\frac{t}{2438.155} }$

d) The amount of radium after 300 years is:

$m(300) \approx 8.842\,g$

4 0

3 years ago

Read 2 more answers