Jane's friend is wrong, the original price would be $200
Answer:
a. n= 47
b. n= 128
Step-by-step explanation:
Hello!
The objective of this experiment is to test if the new catalyst, XA-100, increases the mean hourly yield of a chemical process, that is known to be μ=750 (pounds per hour) with the current process.
You need to calculate the sample size to estimate the population with determined error margins.
To do so, since you have no population information, only that it is approximately normal distributed, you'll use the Student t statistic to get the sample size.
The formula of the margin of error (d) is:
d=
* (
)
I've cleared the sample size of the formula

You need a sample size for the t-Student value and a standard deviation, that's why the information of a pilot study with n=5 and S= 19.62 is given.
a)
95% CI
d= 8 pounds


n= 46.35 ≅ 47
b)
99% CI
d= 5 pounds


n= 127.49 ≅ 128
I hope it helps!
Answer:
See attached picture.
Step-by-step explanation:
The equation is in point slope form
where m is the slope and
is a point.
For the equation y-2 = 23(x+4), graph the point (-4,2). Then from this point count up 23 and over to the right 1.
This is the graph of the line.
Displacement x would be in terms of length, while t would be in terms of time.
Therefore the equation would have units of:
length = (b)*time^2
b = length/(time^2)
Therefore, the units of the constant b should be in length per time^2 (for example, in m/s^2, such as in acceleration).