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3 years ago

PLEASE HELP ME !! I HAVE TO PASS THIS TEST !!

Mathematics

2 answers:

zalisa [80]3 years ago

6 0

Answer: C

Step-by-step explanation:

sergij07 [2.7K]3 years ago

3 0

Answer: 216

Step-by-step explanation:

area =length x width

length =18

Width=12

12x18 =216

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In 2011, a firm books the following: increase in cash, $0; increase in inventories $13; increase in accounts receivable, $29; i

zmey [24]

<span>given: increase in inventories= $13 increase in accounts receivable =$29 increase in accounts payable=$17 solution: change in net working capital = increase in inventories + increase in accounts receivable - increase in accounts payable. change in net working capital = 13+29-17 = $25</span>

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3 years ago

Mark has no basketballs. cat has eight basketballs and Sophia has six balls how many do they have all together?

Aleks04 [339]

14 because Mark has none, Cat has 8 and Sophia has 6 so 8+6=14.

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3 years ago

The radius of a birthday cake is 5 inches. Icing will decorate the top edge of the cake.

maria [59]

Answer:

Step-by-step explanation:

circumference= pi * diameter

diameter= 2 * radius

circumference= pi *2(5)

c= 10pi

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3 years ago

Janet can plant nine feet of carrots in 15 minutes while her daughter Amy can plant 17 feet of carrots in half an hour.

Lena [83]

Answer:

Step-by-step explanation:

In order to find who is more efficient at planting carrots, we want to put both ratios in terms of the same amount of time.

For simplicity, lets see how many carrots each can make in 1 hour.

$Janet:\\9ft \: in \: 15 \:minutes$

$\frac{9ft}{15min} = \frac{xft}{60min}\\x = \frac{60*9}{15} = 36$

Janet can plant 36 feet of carrots in one hour

$Amy:\\\frac{17ft}{30min} = \frac{xft}{60min}\\x = \frac{17*60}{30} = 34$

Amy can plant 34 feet of carrots in one hour

So, Janet can plant carrots more quickly

6 0

3 years ago

The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at

Fynjy0 [20]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.

The mean $\bar X$ = 7.3 days.

The standard deviation = 6.2 days.

df = n-1

$= 30-1 \\ =29$

The importance level is $\alpha$ = 0.10

The table value is calculated with a function excel 2010:

$= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127$

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

$\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}$

$=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\$

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

7 0

3 years ago