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2 years ago

What is the answer to -3/4-1/2

Mathematics

1 answer:

Semenov [28]2 years ago

5 0

Answer:

Steps:

-3/4 - 1/2

-3/4 - 2/4

(-3-2)/4

-5/4

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a branch of mathematics that deals with the study of collecting, analyzing, interpreting, presenting, and organizing data in a p

saw5 [17]

Answer:

Statistics

Step-by-step explanation:

is the application of probability theory, a branch of mathematics, to statistics, as opposed to techniques for collecting statistical data.
the study and manipulation of data, including ways to gather, review, analyze, and draw conclusions from data.

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1 year ago

Read 2 more answers

What is the value of the growth factor of the function? A) 1/5 B) 1/3 C) 2 D) 6

ICE Princess25 [194]

Answer:

Step-by-step explanation:

Divide 18 by one third and see what ya get

then 6, then 2. BOOM!

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2 years ago

Line a is perpendicular to B. if the slope of line A is -3/4 what is the line of B

tatyana61 [14]

Step-by-step explanation:

line a is perpendicular to B.

if the slope of line A is -3/4 what is the line of B

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2 years ago

Find the sum of 1 + 3/2 + 9/4 + …, if it exists.

zmey [24]

Answer:

Option (4)

Step-by-step explanation:

Given sequence is,

$1+\frac{3}{2}+\frac{9}{4}..........$

We can rewrite this sequence as,

$1+\frac{3}{2}+(\frac{3}{2})^2.............$

There is a common ratio between the successive term and the previous term,

r = $\frac{\frac{3}{2}}{1}$

r = $\frac{3}{2}$

Therefore, it's a geometric sequence with infinite terms. In other words it's a geometric series.

Since sum of infinite geometric sequence is represented by the formula,

$S_{n}=\frac{a}{1-r}$ , when r < 1

where 'a' = first term of the sequence

r = common ratio

Since common ratio of the given infinite series is greater than 1 which makes the series divergent.

Therefore, sum of infinite terms of a series will be infinite Or the sum is not possible.

Option (4) will be the answer.

3 0

3 years ago

For which rational expression is 8 an excluded value ? check all that apply

denis23 [38]

Answer:

The correct answer options are C. $\frac{x^2+5}{x-8}$ and D. $\frac{x^2-x-56}{x^2-64}$ .

Step-by-step explanation:

The values which make the denominator equal to zero are called the excluded values.

Here, we can substitute 8 for x and check if it makes the denominator 0.

$\frac{x-8}{x+8} = \frac{8-8}{8+8} =\frac{0}{16} =0$

$\frac{x-2}{x^2-4} = \frac{8-2}{8^2-4} =\frac{6}{60} =\frac{1}{10}$

$\frac{x^2+5}{x-8} = \frac{8^2+5}{8-8} =\frac{69}{0}$

$\frac{x^2-x-56}{x^2-64} = \frac{8^2-8-56}{8^2-64} = \frac{0}{0} =0$

$\frac{8x^2-2}{x^2-16} = \frac{8(8)^2-2}{8^2-16} =\frac{510}{48}$

7 0

2 years ago