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neonofarm [45]
3 years ago
14

What is the answer to -3/4-1/2

Mathematics
1 answer:
Semenov [28]3 years ago
5 0

<u>Answer:</u>

<h2>-5/4</h2>

<u>Steps:</u>

-3/4 - 1/2

-3/4 - 2/4

(-3-2)/4

-5/4

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40 pts and Brainliest pls give detailed answer :)
horsena [70]

Answer:

58 ft

Step-by-step explanation:

So I attached a diagram that illustrates the triangle that is formed. We know an angle, as well as the hypotenuse. We are looking for the height, or in other words the opposite side of the angle. There is a trigonometric function defined as: sin(\theta) = \frac{opposite}{hypotenuse}. Using this we can plug in known values and solve for the opposite side, which I'll simply represent as x.

sin(46) = \frac{x}{80}

Multiply both sides by 80

sin(46) * 80 = x

Calculate sin(46) using a calculator (make sure it's in degree mode)

0.7193398 * 80 = x

Simplify

57.547 \approx x

Round this to the nearest foot

58 \approx x

4 0
2 years ago
Find a b if a = (4,3) and b =(4,5).<br> a. 31<br> C. (16,15)<br> b. (8,8)<br> d.-1
liq [111]
Your answer will be c
8 0
4 years ago
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the actual length of a rectangular platform used for assembeling robots is 6 feet. in amal's drawing, the platform measures 1.2
saw5 [17]

Answer:

Actual width = 5 feet.

Step-by-step explanation:

The ratio of 1.2 to 1  equals the ratio of length to width.

1.2 / 1  = 6 / w  where w is the actual width.

1.2w = 6

w = 6/1.2

w = 5.

3 0
3 years ago
Please help ASAP !!!
enot [183]

Answer: x=3

Step-by-step explanation:

To solve this problem you must apply the proccedure shown  below:

- Multiply both sides of the equation by 3:

3(2x-3)=3(\frac{x^2}{3})\\6x-9=x^{2}

- Now you must make the equation equal to zero as following:

6x-9=x^{2}\\x^{2}-6x+9=0

- Factor it, as you can see below. Therefore, you obtain the following result:

(x-3)(x-3)=0\\(x-3)^2=0\\x=3

 

5 0
3 years ago
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Find the area of a square with a length of 5 cm.
Diano4ka-milaya [45]
<span>area of a square = a^2 = 5^2 = 25

answer
</span><span>area of a square = 25 cm^2</span>
3 0
3 years ago
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