![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
No, he cannot
Step-by-step explanation:
Lets say the student takes the maximum socre on his last test, so he gets 100. Now, his average on the six texts will be:
(75+85+90+95+94+100)/6 = 89.83
So, if taking 100 is not enough to get to the average of 90, this means he would need a score greater than 100, which is impossible as 100 is the maximum. So, the student CAN'T get an A
Answer:
slow down plz
Step-by-step explanation:
there ain't no way that is ur work
Answer:
Benito did
Step-by-step explanation:
a slope is basically rise over run so u can see that he started at -1.
-1 plus 3 is 2
then the run part is just going right one since its a whole number
Answer: move 5 to the left and 2 up
Step-by-step explanation:
first is left or right
- is left
+ is right
The second is up or down
+ is up
- is down
