3 years ago

An atom has 10 total electrons. How would you describe the reactivity of

1 answer:

5 0

Answer: d

explanation:

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Answer:

The answer is " $\bold{4.97 \times 10^{-2}}$ "

Explanation:

Please find the complete question in the attached file.

Equation:

$2SO_2+O_2 \leftrightharpoons 2SO_3$

at $t=0 3.3 \ \ \ \ \ \ \ \ \ \ 0.79$

at equilibrium $3.3-p \ \ \ \ \ \ \ \ \ \ 0.79 - \frac{P}{2} \ \ \ \ \ \ \ \ \ \ \ \ P$

$p= 0.47 \ \ atm\\\\SO_2=3.3-0.47 = 2.83 \ \ atm\\\\O_2= 0.74 -\frac{0.47}{2}=0.74-0.235=0.555 \ atm\\\\K_P=\frac{[PSO_3]^2}{[PSO_2]^2[PO_2]}\\\\$

$=\frac{0.47^2}{2.83^2\times 0.555}\\\\=4.97 \times 10^{-2}$

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