Answer:
The amount of heat absorbed is <u>5.183889 kJ</u> .
Explanation:
In conversion of water to ice it rejects some heat while in conversion of ice to water it absorbs heat which is called latent heat which is given as 6.02 kJ/mol.
The amount of ice given is 15.5 g.
Converting it to moles as the latent heat is given in per moles:
Molecular mass of Hydrogen (H) and Oxygen (O) is 1 u and 16 u respectively.
Molecular mass of water is 18 g ( 
⇒ 2*1+16=18 ).
mole = 15.5/18 ≈ 0.8611 moles
Therefore the amount of heat absorbed by 15.5 g of ice ( 0.8611 moles) = <em>Latent heat * moles
</em>
Heat absorbed = 6.02*0.8611
= 6.02*(15.5/18)
≈ 5.183889 kJ
Answer: The correct option is ALL OF THE ABOVE.
Explanation:
TITRATION is a type of volumetric analysis which is used for determining the concentration of solutions. In this process a specific volume of a solution is placed in a conical flask by means of a pipette and small quantities of a second solution is slowly added from a burette until the end point is reached. This is determined by a means of an indicator which shows a characteristic colour change.
During titration, the following precautions should be followed to avoid errors and maintain standardisation in the experiment.
--> Any air bubble in the burette and pipette must be removed during measurement
--> the burette tap should be tightened to avoid leakage.
--> Remove the funnel from the burette before taking any reading to avoid errors in reading the volume.
--> use the base solution such as Sodium Hydroxide Solution to rinse the burette after washing with soap and tap water:
• to remove any air bubble and fill it's tip
• to remove any residual liquid from the water and soap solution which may interfere with the results of the experiment.
• to check if the burette is in good condition.
Therefore all of the above options to the question are correct.
Electrons uniting with electrons of another atom is the cause in this relationship. The effect is a chemical change.
A. A force that acts on a body moving in a circular path
Answer:
please explain further and i maybe can help you
Explanation:
