Question

One component of smog is nitrogen

Answer 1

Answer:

V = 5.97 L

Explanation:

Hello!

In this case, according to the ideal gas law:

$PV=nRT$

We would need to solve for V as we know the temperature and pressure as the gas it at STP conditions (273 K and 1 atm respectively):

$V=\frac{nRT}{P}$

Next, we compute the moles in 8 g of NO, given its molar mass of 30.01 g/mol:

$n=\frac{8g}{30.01g/mol}=0.267mol$

Therefore, we obtain the following volume:

$V=\frac{0.267mol*0.08206\frac{atm*L}{mol*K}*273K}{1atm}\\\\V=5.97 L$

Best regards!