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inessss [21]
3 years ago
13

One component of smog is nitrogen

Chemistry
1 answer:
devlian [24]3 years ago
7 0

Answer:

V = 5.97 L

Explanation:

Hello!

In this case, according to the ideal gas law:

PV=nRT

We would need to solve for V as we know the temperature and pressure as the gas it at STP conditions (273 K and 1 atm respectively):

V=\frac{nRT}{P}

Next, we compute the moles in 8 g of NO, given its molar mass of 30.01 g/mol:

n=\frac{8g}{30.01g/mol}=0.267mol

Therefore, we obtain the following volume:

V=\frac{0.267mol*0.08206\frac{atm*L}{mol*K}*273K}{1atm}\\\\V=5.97 L

Best regards!

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Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility.
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The molar solubility is 7.4×10^{-3} M and the solubility is  7.4×10^{-3} g/L .

Calculation ,

The dissociation of silver bromide is given as ,

AgBr → Ag ^{+} + Br^{-}

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Ksp =  [Ag ^{+} ] [ Br^{-} ]  =  [S] [ S ] = S^{2}

S = √ Ksp = √ 5. 5×10^{-5} = 7.4×10^{-3}

The solubility =7.4×10^{-3} g/L

The molar solubility is the solubility of one mole of the substance.

Since ,  one mole of AgBr is dissociates and form one mole of each  Ag ^{+} and Br^{-} ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4×10^{-3} mol/L = 7.4×10^{-3} M

To learn more about molar solubility ,

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