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Novay_Z [31]
3 years ago
10

A student wants to measure the entropy of ice. What should the student do?

Chemistry
1 answer:
Helen [10]3 years ago
6 0

Answer: Option (c) is the correct answer.

Explanation:

Entropy is defined as the degree of randomness. This means that more is the number of collisions taking place between atoms of a substance more will be the randomness.

Therefore, more will be the entropy of substance. We cannot measure the entropy but we can measure the change in entropy of a substance.

A thermometer is a glass tube that contains a liquid column generally mercury, and it is usually used to measure the temperature of human body.

A calorimeter is a device or apparatus that is used in a chemical reaction to measure the amount of heat involved.

Therefore, we can conclude that the student can't measure entropy directly, only an entropy change.

 

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Which of the following statements is true?
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Answer:

C. Lithium is most easily oxidized of the metals listed on the activity series and therefore it will most easily give electrons to metal cations

Explanation:

"Lithium" is a type of alkali metal that has a "single valence electron." Since it is a reactive element, it easily gives up an electron when it is combined with other elements. Such giving up of electron is meant to create compounds or bonds.

Among the common metals listed, "lithium" is the most easily oxidized. This means that it donates its electrons immediately. Such combination makes it exist as a<em> "cation"</em> or <em>"positively-charged."</em>

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Hunter-Best [27]
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The volume of a gas at 17.5 psi decreases from 1.8L to 750mL. What is the new pressure of the gas in arm?
Maurinko [17]

Answer:

P₂ = 2.88 atm

Explanation:

Given data:

Initial volume of gas = 1.8 L

Final volume = 750 mL

Initial pressure = 17.5 Psi

Final pressure = ?

Solution:

We will convert the units first:

Initial pressure = 17.5  /14.696 = 1.2 atm

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The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.2 atm × 1.8 L =  P₂  ×0.75 L

P₂ = 2.16 atm. L/ 0.75 L

P₂ = 2.88 atm

4 0
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That’s not very specific

Explanation:

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