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Novay_Z [31]
3 years ago
10

A student wants to measure the entropy of ice. What should the student do?

Chemistry
1 answer:
Helen [10]3 years ago
6 0

Answer: Option (c) is the correct answer.

Explanation:

Entropy is defined as the degree of randomness. This means that more is the number of collisions taking place between atoms of a substance more will be the randomness.

Therefore, more will be the entropy of substance. We cannot measure the entropy but we can measure the change in entropy of a substance.

A thermometer is a glass tube that contains a liquid column generally mercury, and it is usually used to measure the temperature of human body.

A calorimeter is a device or apparatus that is used in a chemical reaction to measure the amount of heat involved.

Therefore, we can conclude that the student can't measure entropy directly, only an entropy change.

 

You might be interested in
Does liquid evaporate with adding heat or losing it
Marysya12 [62]
Adding because evaporation speed is increased with increased temperature
6 0
3 years ago
What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?
Ymorist [56]

Answer:

\% diss = 50\%

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}

Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

Ka=\frac{x^2}{[HA]_0-x} =10^{-4.74}=1.82x10^{-5}

Thus, it is possible to find x given the pH as shown below:

x=10^{-pH}=10^{-4.74}=1.82x10^{-5}M

So that we can calculate the initial concentration of the acid:

\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\

[HA]_0=3.64x10^{-5}M

Therefore, the percent dissociation turns out to be:

\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%

Best regards!

6 0
2 years ago
On a coordinate plane, which single transformation could map point A (3,-4) onto point A' (1.5,-2)? *
Ksenya-84 [330]

Answer: A dilation with rule: (x,y)\to(\dfrac12x,\dfrac12y)

Explanation:

A dilation is a non-rigid transformation that creates an image that is the same shape as the original but has a different size.

It uses a scale factor k such that

(x,y)\to(kx,ky)

(x,y)= coordinates of original figure

(kx,ky) = corresponding coordinate in the image.

To transform: A (3,-4) onto point A' (1.5,-2).

Using scale factor k= \dfrac12, we have

A(3,-4)\to A'(\dfrac12\times3, \dfrac12\times-4)=A'(1.5,-2)

Required rule: (x,y)\to(\dfrac12x,\dfrac12y)

3 0
2 years ago
4. (01.05 MC)
DochEvi [55]

Answer:

The correct option is;

The gas particles move faster, have the same molecular composition, and have weaker attractions between them than the liquid particles

Explanation:

The properties of the gas molecules in comparison to liquids are

1) The gas molecules are widely spread out

2) After evaporation and while in conditions favorable to the gaseous state, the kinetic energy of a gas is larger than the inter molecular attractive forces

3) A gas fills the container in which it is placed

For liquids

1) There are strong intermolecular forces holding the molecules together in a liquid

2) Liquid attractive forces in a liquid are strong enough to hold neighboring molecules

3) The volume of a liquid is definite.

5 0
3 years ago
Epsom salt, a common hydrate, has the formula shown below. If I measure out 125 g of epsom salt to add to my foot soak, what mas
tatiyna

Answer:

The answer to your question is 64.02 g of H₂O

Explanation:

Data

Mass of magnesium sulfate hepta hydrated = 125 g

Mass of water = ?

Process

1.- Calculate the molar mass of the salt and the molar mass of water

molar mass of MgSO₄ 7H₂O = 24 + 32 + 64 + 14 + 112 = 246 g

mass of H₂O = 2 + 16 = 18 g

2.- Use proportions to calculate the mass of water in the epsom salt

                246 g MgSO₄ 7H₂O------------------------- 126 g of H₂O

                125 g                        -------------------------   x

                x = (125 x 126)/246

                x = 15750/246

               x = 64.02 g of H₂O

6 0
2 years ago
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