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andre [41]
3 years ago
8

A 0.1 M solution enatiomerically pure chemical compound D has an observed rotation of 0.20 degrees in a 1 atm sample container.

The Molecular mass of the compound is 150.
a. What is the specific rotation of D?(I already know this part )
b. What is the observed rotation if this solution is mixed with an equal volume of a solution that is 0.1 M in L, the enantiomer of D?
c What is the observed rotation if the solution of D is diluted with an equal volume of solvent?
d What is the specific rotation of D after the dilution described in c?
Chemistry
1 answer:
Norma-Jean [14]3 years ago
8 0
<span>What is the specific rotation of L, an enantiomer of D? the same than D but opposite sign. f. What is the observed rotation of 1 L of solution that contains 0,01 mole of D and 0.005 mole of L? (Assume 1 dm path length) calculate the difference between the two enantiomers 0.01 D- 0.05 L = 0.05 M "D" specific rotation = observed rotation/ (cell path x concentration) cells path = 1dm (doesn't affect anything in the formula we can ignore it) observed rotation = specific rotation D x concentration D</span>
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