All categories

3 years ago

What is this shape? I am doing this for my homework I have 7hrs to do it

Mathematics

1 answer:

liberstina [14]3 years ago

7 0

I think it’s called tromino

You might be interested in

Which solid has one face, zero lateral faces, one base, one vertex, and zero edges?

Ratling [72]

The correct answer is cone.

There's only one face, and only one vertex that leads to a single base. There are no edges because the base perimeter is not considered to be an edge because it's a vertex.

7 0

3 years ago

At a middle school, 30% of the students walk to school, 1/5 (20%) ride their bikes, 12.5 are dropped off by car, and the remaini

Vitek1552 [10]

Answer:

please give more clarification

4 0

3 years ago

Read 2 more answers

Help !! Please I can’t find the answer

SVETLANKA909090 [29]

Answer:

$\large\boxed{r^2=(x+5)^2+(y-4)^2}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have diameter endpoints.

Half the length of the diameter is the length of the radius.

The center of the diameter is the center of the circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the given points (-8, 2) and (-2, 6):

$d=\sqrt{(6-2)^2+(-2-(-8))^2}=\sqrt{4^2+6^2}=\sqrt{16+36}=\sqrt{52}$

The radius:

$r=\dfrac{d}{2}\to r=\dfrac{\sqrt{52}}{2}$

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-2)}{2}=\dfrac{-10}{2}=-5\\\\y=\dfrac{2+6}{2}=\dfrac{8}{2}=4$

$(-5,\ 4)\to h=-5,\ k=4$

Finally:

$(x-(-5))^2+(y-4)^2=\left(\dfrac{\sqrt{52}}{2}\right)^2\\\\(x+5)^2+(y-4)^2=\dfrac{52}{4}\\\\(x+5)^2+(y-4)^2=13$

5 0

3 years ago

Triangle TRE has vertices T(3,6), R(-3,10), and E(-9,4). Find the coordinates of point M if line TM is a median of triangle TRE

Sergeeva-Olga [200]

Answer:

The coordinate of point M = (-6,7)

Explanation:

The Median of a triangle is a line segment from a vertex to the midpoint of the opposite side of a triangle.

Given: $\triangle TRE$ has vertices T(3,6) , R(-3,10) and E(-9,4).

Here, line TM is a median of triangle TRE where M is the midpoint of RE.

The midpoint of M of the line segment from R(-3,10) to E(-9,4) is;

M = $(\frac{-3+(-9)}{2}, \frac{10+4}{2}) = ( \frac{-12}{2}, \frac{14}{2} )=(-6,7)$

Therefore, the coordinate of point M is, (-6,7).

7 0

3 years ago

HELP WILL GIVE BRAINLY PL. What is the sign of f3•(-g)^3?

Nastasia [14]

Answer:

Negitive

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers