(g/3)-10 or g÷3-10
This is g divided by 3 minus 10
Answer:
I18 - xI such that x < 18.
ok, first let's what happens if x = 18:
I18 - xI = I18 - 18I = 0
So, at the moment we have the condition:
I18 - xI > 0.
now, if x is a really large negative number, suppose, x = -100
I18 + 100I = I118I = 118
So, as x can freely move in the negative range, we can see that I18 - xI can be any positive number, so the only restriction that we have is:
I18 - xI > 0.
This means that the domain is:
D = (-∞, 18)
and the range is:
R = (0, ∞)
The correct answer is: " √x − <span>2√b " .
</span>_________________________________________________________
The "conjugate" of " √x + 2√b " is: " √x − 2√b " .
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Explanation:
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In an expression with 2 (TWO) terms; that is, in a "binomial expression",
the "conjugate" of that expression refers to that very expression — with the "sign" in between those two terms—"reverse" (e.g. "minus" becomes "plus" ; or, "plus" becomes "minus" .) .
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→ So: We are given: " <span>√x + 2√b " .
</span>
→ Note that this is a "binomial expression" ;
→ that is, there are 2 (TWO) terms: " <span>√x " ; and: " 2√b " .
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To find the "conjugate" of the given binomial expression:
</span>→ " <span>√x + 2√b " ;
</span>→ We simply change the "+" {plus sign} to a "<span>−" {minus sign} ; and rewrite:
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</span>→ " √x − 2√b " ;
→ which is the "conjugate" ; and is the correct answer:
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→ " √x − 2√b " ; is the "conjugate" of the expression: " <span>√x + 2√b " .
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</span>→ {that is: " √x − 2√b " ; is the conjugate.}.
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Answer:
Greatest number: 9
Least number: 2
Range: 7
Step-by-step explanation:
From smallest to largest, the numbers are: 2, 3, 6, 8, 9. The largest (greatest) is 9 and the least (smallest) is 2. The range is 9-2=7.
Answer:
3 ÷ 1/3 = 9
Step-by-step explanation:
= 3 ÷ 1/3
= 3/3 (3/1) ÷ 1/3
= 9/3 × 3/1
= 9/1
= 9
