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Umnica [9.8K]
3 years ago
6

- 28 5 + 3 y help pls

Mathematics
1 answer:
Mariulka [41]3 years ago
8 0

Answer:

-282y

Step-by-step explanation:

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. What part of an hour is your school lunch time?
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Answer: It's from 11:02 till 11:35. hbu?

Step-by-step explanation:

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3 years ago
You are working as an apprentice for the bksb Newcastle Arena.
Advocard [28]
To find the area of the arena, you will need to find the areas of the rectangular spaces and the 2 semicircles. Because the formulas are given, I will just substitute in the values and show the work for finding the areas.

To find the perimeter, you will look at the distances of lines that take you around the space. Because two of these spaces are half circles, you will need to find the circumference of the full circle.

Also, the answers need to be given in meters, so all units given in centimeters will be divided by 100 to convert them to meters.

Perimeter:

C= 3.14 x 20 m
C = 62.8 meters

62.8 + 8 + 25 + 8 + 5 + 8 + 10 + 8 + 40= 174.8 meters for the Perimeter

Area:
A = 25 x 8
A = 200 square meters

A = 10 x 8
A = 80 square meters

A = 20 x 40
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A = 3.14 x 10^2
A = 314 square meters

Total Area: 314 + 800 + 80 + 200= 1394 square meters
8 0
3 years ago
Need help people please help me
Ugo [173]

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4 0
3 years ago
Identify the cross section of the solid shown in the diagram
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Step-by-step explanation:

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6 0
3 years ago
An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha
TEA [102]

Answer:

The probability is   P(X  >300 ) = 0.97219

Step-by-step explanation:

From the question we are told that

 The capacity of  an Airliner  is  k =  300 passengers

 The sample size n =  320 passengers

  The probability the a randomly selected passenger shows up on to the airport

    p = 0.96

Generally the mean is mathematically represented as

    \mu  =  n*  p

  => \mu  =  320 *  0.96

    => \mu  = 307.2

Generally the standard deviation is  

    \sigma =  \sqrt{n *  p *  (1 -p ) }

=>  \sigma =  \sqrt{320  *  0.96 *  (1 -0.96 ) }

=> \sigma =3.50

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

  P(X  > k ) =  P( \frac{ X -\mu }{\sigma }  >  \frac{k - \mu}{\sigma } )

Here \frac{ X -\mu }{\sigma }  =Z (The \ standardized \  value \  of  \ X )

=>P(X  >300 ) =  P(Z >  \frac{300 - 307.2}{3.50} )

Now applying  continuity correction we have

    P(X  >300 ) =  P(Z >  \frac{[300+0.5] - 307.2}{3.50} )    

=>    P(X  >300 ) =  P(Z >  \frac{[300.5] - 307.2}{3.50} )

=>    P(X  >300 ) =  P(Z >  -1.914 )

From the z-table  

    P(Z >  -1.914 ) =  0.97219

So

    P(X  >300 ) = 0.97219

8 0
3 years ago
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