- 28 5 + 3 y<br><br> help pls

Find the length of the third side. If necessary, write in simplest radical form.

Angelina_Jolie [31]

Answer:

the length of the missing side is 2

Step-by-step explanation:

Use a^2 + b^2 = c^2

a = 4

b = ?

c = 2sqrt5

4^2 + b^2 = (2sqrt5)^2

16 + b^2 = 20

subtract 16 from both sides

b^2 = 4

take the sqrt of both sides

b = 2

3 0

2 years ago

Read 2 more answers

A water tank fills as shown in the graph below.

qaws [65]

I think the answer is 1/3 but i suck at slopes lol. Might wanna double check

8 0

3 years ago

Read 2 more answers

Solve 3x + 23 + x = 7. x = −4 x = 4 x = −0.25 x = 0.25

Maksim231197 [3]

<h2>______________________________</h2><h2>Solve for x | Solution and Explanation </h2>

______________________________________________

Hello! So...

We are given the following:

Solve for x.

$3x+23+x=7$

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1. Group the like terms.

$3x+x+23=7$

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2. Add similar elements ( $3x+x=4x$ ).

$4x+23=7$

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3. Subtract 23 from both sides.

$4x + 23 - 23 = 7 - 23$

====================

4. Simplify.

$4x=-16$

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5. Divide both sides by 4.

$\frac{4x}{4} =\frac{-16}{4}$

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6. Simplify.

$x=-4$ (aka. Option A)

====================

Hope this helps!

3 0

1 year ago

The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m

larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words $=\frac{13!}{4\times 2!\times 3!}=64,864,800$

When M's are together . considering 2 M's as one

therefore there are $\frac{12!}{3\times 2!\times 3!}=9,979,200$

No of ways $=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600$

(b)No of ways such that M's are separated by at least 2 letters

at least 2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

$=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

$=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

$=45738000$

7 0

3 years ago

Can someone complete the square

pshichka [43]

To do these, start by looking at the "b" value -6.
divide it by 2

-6/2 = -3

now square this number

(-3)^2 = 9

this is what you need for the "c" value

there is only a 5 for the c value so add 4 to both sides of the equation. ( +4 = +4)

y +4 = x^2 -6x +5 +4
y +4 = x^2 -6x +9
y +4 = (x -3)^2
y = (x -3)^2 - 4

vertex ( 3, -4) upwards facing like a bowl, because the "a" value is positive. So the vertex is the minimum, lowest point on the graph.

7 0

3 years ago

- 28 5 + 3 y help pls