The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
<h3>How to determine the slope?</h3>
The interval is given as:
x = 2 to x = 5
The slope is calculated as:
<u>16. y = 3x - 4</u>
Substitute 2 and 5 for x
y = 3*2 - 4 = 2
y = 3*5 - 4 = 11
So, we have:
Divide
m = 3
Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3
<u>17. y = 2x^2-4x - 2</u>
Substitute 2 and 5 for x
y = 2 * 2^2 - 4 * 2 - 2 = -2
y = 2 * 5^2 - 4 * 5 - 2 = 28
So, we have:
Divide
m = 10
Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
Read more about slopes at:
brainly.com/question/3605446
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Inequlity: 15>= x
Greatest amount she can earn: $105 a week
Answer:
18
Step-by-step explanation:
53.83 rounds to 54
36.464 rounds to 36
54-46=18
Answer:
Step-by-step explanation:
We are given two points, the y - intercept and the x - intercept.
The y - intercept being: ( 0, -7 )
The x - intercept being: ( 1, 0 )
The equation of a line in slope - intercept form is:
y = mx + b, where m is the slope and b is the y - intercept.
We already have the y - intercept. So far we have:
y = mx - 7
What we're missing is the slope.
To find the slope, we can use this formula:
, where 
and 
are the x - coordinates of both points and 
and are the y - coordinates of both points.
We now have the missing piece, the slope, so the equation now is:
Answer: The closest answer I got is 9 5/6 hours
