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forsale [732]
3 years ago
7

You are buying pizzas for a neighborhood party. Each pizza costs $9 and you want to tip the delivery guy $5. You have $72.

Mathematics
2 answers:
shusha [124]3 years ago
4 0

Answer:

7

Step-by-step explanation:

72-5=67, 67/9=7.444 but you cant round up because you dont have 8 dollars still, so you round down, getting you 7.

Hope this helps! & have a good christmas :)

TiliK225 [7]3 years ago
3 0

Answer:

7 pizzas

Step-by-step explanation:

You just minus 72 from 9 and once you get to 9 dollars you still have enough to time the delivery guy and you would have 4 dollars left.

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IMPORTANT PLZ HELP!!!!
kolbaska11 [484]

Answer:

D

Step-by-step explanation:

|C|<|D|

So C≠D

6 0
3 years ago
A store sells four printers for every five computers. The store sells 40 computers on Saturday. How many printers did it sell on
aleksley [76]
32 printers were sold:
P:C
4:5
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40/5=8
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3 0
2 years ago
at a bus station , buses depart at a rate of 3 every 10 minutes. at this rate, _____buses will depart in 1 hour
Marina CMI [18]

1 hour = 60 minutes

60 minutes /  10 minutes = 6

So 6 times in one hour 3 buses depart.


6 x 3 = 18 total buses in an hour.

6 0
3 years ago
There are 23 red shirts and 16 white shirts they will be put onto shelves in piles of 8 how many shirts will not fit evenly into
Mama L [17]

Given :

There are 23 red shirts and 16 white shirts they will be put onto shelves in piles of 8.

To Find :

How many shirts will not fit evenly into 8 piles.

Solution :

We need to find the number of shirts which will not fit evenly into 8 piles.

What we need is the remainder of 23 divided by 8.

23 = 8×2 + 7

So, their are 7 shirts which will not fit evenly.

Hence, this is the required solution.

6 0
3 years ago
I NEED HELP QUICKLY!!! What is the sum of the first 140 positive multiples of 3?
garri49 [273]

Answer:

C

Step-by-step explanation:

The multiples of 3 are

3, 6, 9, 12, 15, ...........

The terms form an arithmetic sequence with common difference of 3.

The sum to n terms is

S_{n} = \frac{n}{2} [2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = 3 and d = 3, thus

S_{140} = \frac{140}{2} [ (2 × 3) + (139 × 3) ]

                            = 70(6 + 417) ] = 70 × 423 = 29610 → C

5 0
3 years ago
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