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ryzh [129]
3 years ago
12

Write an equation in point-slope form for the line that passes through

Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:

Point-slope form:

y-5= -1/3 times (x+9)

This is only for the first part

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Answer:

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3 years ago
Write an equation of the line that goes through the point (6, 12) and has a slope of 2 3 .
Degger [83]

Answer:

3y = 2x + 24

Step-by-step explanation:

The correct question is as follows;

Write an equation of the line that goes through the point (6, 12) and has a slope of 2/3

Solution

Here, we have a point and a slope, and we want to write the equation of the line

The method we shall use here is the point slope method

Mathematically, that will be;

y-y1 = m(x-x1)

(x1,y1) = (6,12)

m = 2/3

y-12 = 2/3(x-6)

3(y-12) = 2(x-6)

3y-36 = 2x - 12

3y = 2x -12 + 36

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3 years ago
What is the value of k when the expression 3(7 + x) is equivalent 3(x + k)
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Answer:7

Step-by-step explanation:

8 0
3 years ago
What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?
s344n2d4d5 [400]

Answer:

2 units

Step-by-step explanation:

The given equation of the circle is:

x^{2} + y^{2}+8x-6y+21=0

The general equation of the circle is:

x^{2} + y^{2}+2gx+2fy+c=0

Comparing the given equation with the general equation we can say:

g = 4

f = -3

c = 21

The formula for radius of the circle is:

radius=\sqrt{g^{2} +f^{2} -c }

Using these values of the given circle, we get:

radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2

Therefore, the length of radius of the given circle is 2.

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