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3 years ago

In 5 cricket innings Sarah had an average of 45 runs per innings.

1 answer:

8 0

Sarah you failure why are you playing cricket.

But anyway, Sarah should score 75 runs in her sixth inning to reach an average of 50. To solve, first multiply 45 by 5 to reverse the division used to find her previous average. You should get 225. We want the score added to 225, the addend of them being divided by 6 to get 50, her average. Continue by putting your variables into an equation, then simplifying. Below, I distributed the division of the 6, then subtracted 37.5 from both sides of the equation, and finally multiplied both sides by 6 to get our final answer, a score of 75.

(225 + x)/6 = 50

37.5 + x/6 = 50

x/6 = 12.5

x = 75

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in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago

1. y = (x - 5)3 what are the zeros and multiplicity

Elden [556K]

Answer:

$\frac{5}{3}$ =x

Step-by-step explanation:

0=(x-5)3

0=(3x-5)

5=3x

$\frac{5}{3}$ =x

3 0

4 years ago

Find the value of x to the nearest tenth.

Tju [1.3M]

Answer:

around 4.1

Step-by-step explanation:

Using Pythaogrean theorem we get sqrt 32 or 4sqrt2 for the diagonal of the square.

To get x we can use Pythagorean theorem again to set up an equation,

32 + x^2 = 49

This gives us x = sqrt17, which is approximately 4.1231 or around 4.1

4 0

3 years ago

Read 2 more answers

A. A group of twelve art students are visiting a local art museum for a field trip. The total cost of admission for the students

Shalnov [3]

Answer:

a) $10.42

b) 11 trips

c) 10 cookies

d) 12/125ths of a cheesecake (or 9.6%)

Step-by-step explanation:

Let x = the cost of admission for each student

Let y = the total cost of admission

⇒ y = 12x

⇒ 125 = 12x

⇒ x = 125 ÷ 12

⇒ x = 10.42

So the cost of admission for each student = $10.42

Let x = the number of trips

Let y = the total number of passengers

⇒ y = 12x

⇒ 125 = 12x

⇒ x = 125 ÷ 12

⇒ x = 10.42

Therefore, the van must make 11 trips in order to bring 125 passengers to the same location. (If it took 10 trips, then it would only bring 120 passengers, hence why we have to round make 11 trips to bring the last 5 passengers).

Let x = the number of cookies each neighbor will receive

Let y = the total number of baked cookies

⇒ y = 12x

⇒ 125 = 12x

⇒ x = 125 ÷ 12

⇒ x = 10.42

Therefore, each neighbor will receive 10 cookies (we have to round it down, as if each neighbor received 11 cookies, we would need 132 in total).

Let x = the number of cheesecakes purchased

Let y = the amount of cheescake each guest will receive

⇒ y = 125x

⇒ 12 = 125x

⇒ x = 12 ÷ 125

⇒ x = 12/125 = 0.096 = 9.6%

Therefore, each guest will receive 12/125ths of a cheesecake (or 9.6%).

6 0

2 years ago

What is the length of the missing leg? If necessary, round to the nearest tenth.

BabaBlast [244]

Answer:

The length of the hypotenuse is 40 mm.

Step-by-step explanation:

We can solve for 'a' using Pythagoras theorem. Let's solve it.

10² = 5² + a²
=> 100 = 25 + a²
=> a² = 75
=> a = 8.660
=> a = 8.7

Hence, the length of the hypotenuse is 8.7 m.

Hoped this helped.

$BrainiacUser1357$

7 0

2 years ago