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Eddi Din [679]
3 years ago
7

In 5 cricket innings Sarah had an average of 45 runs per innings.

Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0
Sarah you failure why are you playing cricket. 

But anyway, Sarah should score 75 runs in her sixth inning to reach an average of 50. To solve, first multiply 45 by 5 to reverse the division used to find her previous average. You should get 225. We want the score added to 225, the addend of them being divided by 6 to get 50, her average. Continue by putting your variables into an equation, then simplifying. Below, I distributed the division of the 6, then subtracted 37.5 from both sides of the equation, and finally multiplied both sides by 6 to get our final answer, a score of 75. 

(225 + x)/6 = 50 

37.5 + x/6 = 50  

x/6 = 12.5 

x = 75
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Answer:

similarly,on the graph in vertical line,x only takes value.thus, the equation for a vertical line is x=a,where is a value that x takes.

7 0
2 years ago
Ordered pair is a solution of equation y=3x-7
Xelga [282]
Add 7 to both sides
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6 0
4 years ago
2a + b = 3 and a - 3b = 5
vfiekz [6]

Answer:

a= 2 b=-1

Step-by-step explanation:

a-3b=5

or, a= 5+3b_(i)

substituting value of a in 2a+b=3,

2×(5+3b)+b=3

or, 10+6b+b=3

or, 7b=3-10

or, 7b=-7

b= -1

substituting value of b in(i),

a=5+3b

=5+3×(-1)

=5-3

=2

6 0
3 years ago
Three fair dice are rolled, one red, one green and one blue. What is the probability that the upturned faces of the three dice a
r-ruslan [8.4K]

Answer:   \dfrac{5}{9}

Step-by-step explanation:

When we throw a die , Total outcomes =6

When we throw 3 dice , Total outcomes = 6 x 6 x 6 = 216 [by fundamental counting principle]

Given : Three fair dice are rolled, one red, one green and one blue.

Favorable outcomes : When the upturned faces of the three dice are all of different numbers i.e. no repetition of numbers allowed

By Permutations , the number of favorable outcomes = ^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6!}{3!}=6\times5\times4=120

The probability that the upturned faces of the three dice are all of different numbers = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

=\dfrac{120}{216}=\dfrac{5}{9}

The probability that the upturned faces of the three dice are all of different numbers  is \dfrac{5}{9} .

7 0
3 years ago
nicole is flying two kites. she has 104 feet of string out to one kite and 110 feet out to the other kite. the angle formed by t
tankabanditka [31]

Answer:

Step-by-step explanation:

Answer:

48.49 feet

Step-by-step explanation:

The diagrammatic sketch of the details given in the question was attached in the picture below.

From the picture below, the distance between the two kites is represented by (c) and can be calculated by using the cosine angle rule which is illustrated as:

c^2 = a^2 + b^2 -2ab cos \ C

where;

a = 110

b = 104

Cos C = 26°

Then;

c^2 = 110^2 + 104^2 -2(110)(104) cos \ 26 \\ \\  c^2 = 12100 + 10816- 22880 ( 0.8988) \\ \\  c^2 = 22916- 20564.544 \\ \\  c^2 = 2351.456 \\ \\  c= \sqrt{2351.456} \\ \\ \mathbf{ c = 48.49 \ feet}

8 0
3 years ago
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