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Ipatiy [6.2K]
3 years ago
14

Express the product of x+1 and x+8 in standard quadratic form.

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
8 0
(x+1)*(x+8) = x^2 + 9x + 8
bulgar [2K]3 years ago
7 0
(x + 1)(x + 8)

x(x + 8) + 1(x + 8)

x*x + 8*x + 1*x + 1*8

x² + 8x + x + 8

x² + 9x + 8

Hope this explains it.
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Multiplication in GF(24 ): Compute A(x)B(x) mod P(x) in GF(24 ) using the irreducible polynomial P(x) = x 4 + x + 1, where A(x)
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Answer:

Step-by-step explanation:

hello,

i advice you check the question again if it is GF(2^{4}) or GF(24). i believe the question should rather be in this form;

multiplication in GF(2^{4}): Compute A(x)B(x) mod P(x) = x^{4} + x+1, where A(x)=x^{2}+1, and B(x)=x^{3} + x+1.

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)=(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1  ) = (x^{5} +x^{3}+x^{2}  ) + (x^{3}+x+1  ) mod (x^{4} + x+1 )

= x^{5}+2x^{3} +x^{2}  + x + 1 mod(x^{4}+x+1  )

=2x^{2} +1

please note that the division by the modulus above we used

\frac{x^{5}+2x^{3}+x^{2} +1  }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}

5 0
3 years ago
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Step-by-step explanation:

f(x)=3x^6+2x^5+x4-2x^3

The number of roots is determined by the degree of the polynomial.  They may be real or complex.

Since this is a 6th degree polynomial, it will have 6 roots

f(x)=3x^6+2x^5+x4-2x^3


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4 years ago
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