Answer:
a
Step-by-step explanation:
Answer:
The answer is 4z^2 + 7z
Step-by-step explanation:
7z + 4z^2 +6 - 6
So, just combine like term which is 6 - 6 = 0
So, the remaining is 4z^2 + 7z that cannot be simplified anymore
Answer:
bags of snack = x = 6
bottles of water = y = 5
Step-by-step explanation:
The system of equations can be used to determine how many of each item they bought.
20.00=2.50x+1.00y
11=x+y
how many bags of snack mix did they buy?
Let
bags of snack = x
bottles of water = y
20.00 = 2.50x + 1.00y (1)
11 = x + y (2)
From (2)
x = 11 - y
Substitute x = 11 - y into (1)
20.00 = 2.50x + 1.00y
20.00 = 2.50(11 - y) + 1.00y
20.00 = 27.5 - 2.50y + 1.00y
20.00 - 27.5 = -2.50y + 1.00y
-7.5 = -1.5y
y = -7.5/-1.5
y = 5
Substitute y = 5 into (2)
11 = x + y
11 = x + 5
11 - 5 = x
x = 6
bags of snack = x = 6
bottles of water = y = 5
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
