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3 years ago

PC

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

4 0

The answer is: Perpendicular, because both equations intersects or cross over each other. There is an attached photo

abruzzese [7]3 years ago

3 0

The lines are perpendicular because their slopes are opposite reciprocals of each other (4 and -1/4).

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9.7q = 9.1q - 7.92 q =

AleksAgata [21]

Answer:

q = -13.2

Step-by-step explanation:

9.7q = 9.1q - 7.92

Subtract 9.1q from both sides.

0.6q = -7.92

Divide both sides by 0.6

q = -13.2

Double check your work.

9.7(-13.2) = 9.1(-13.2) - 7.92

-128.04 = -120.12 - 7.92

-128.04 = -128.04

5 0

3 years ago

What is the remainder when (x3 + 1) is divided by (x2 – x + 1)? x + 1 x 2 0

Furkat [3]

If I’m not wrong I think it’s x+1

8 0

3 years ago

Please Help.

Gennadij [26K]

Answer:
amount of nuts = 2 pounds
amount of dried fruit = 4 pounds

Explanation:
We are given that x is the amount of nuts and y is the amount of dried fruit.
We are also given that:
1- Hunter needs to make 6 pounds of trail mix. This means that:
x + y = 6
This can be rewritten as:
x = 6 - y .........> equation I
2- x costs $4 per pound, y costs $3.5 and Hunter can spend a total of $22. This means that:
4x + 3.5y = 22 ..........> equation II

Substitute with equation I in equation II and solve for y as follows:
4x + 3.5y = 22
4(6-y) + 3.5y = 22
24 - 4y + 3.5y = 22
24-22 = 4y-3.5y
2 = 0.5y
y = 4 pounds

Substitute with y in equation I to get the value of x as follows:
x = 6-y
x = 6-4
x = 2 pounds

Hope this helps :)

7 0

4 years ago

Help please I'm stuck show and explain your work

Deffense [45]

The expressions D, E, and F represent a correct solution to the equation.

Step-by-step explanation:

Step 1:

First, we need to solve the given equation and find the value of x which satisfies the equation.

$6(x+4)=20, (x+4) = \frac{20}{6} = 3.333,$

$x = 3.333 - 4 = -0.666.$

So the value of x for the given equation is -0.666.

Step 2:

Now we evaluate the values of the six given options to see which ones have an x value of -0.666.

A. $\frac{20-4}{6}= \frac{16}{6} = 2.666,$

B. $\frac{1}{6} (20-4)= \frac{1}{6} (16)=\frac{16}{6} = 2.666,$

C. 20 -6 -4 = 20 - 10 = 10.

D. $\frac{20}{6} -4= 3.333 - 4 = -0.666,$

E. $\frac{1}{6} (20-24) = \frac{1}{6} (-4)= -0.666,$

F. $(20-24)\frac{1}{6} = (-4)\frac{1}{6} = -0.666.$

So the options D, E, and F represent a correct solution to the given equation.

7 0

4 years ago

A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr

worty [1.4K]

Answer: The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation: Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8 and n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.$

Now, the probability of pulling three green marbles out with replacement is given by

$P(G)\times P(G)\times P(G)=\dfrac{5}{25}\times\dfrac{5}{25}\times \dfrac{5}{25}=\dfrac{1}{125}=\dfrac{1}{125}\times100\%=0.8\%.$

Thus, the probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

4 0

3 years ago