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Alex73 [517]
3 years ago
11

The length of a rope from an attic window to tree house is 500 yards. If someone slides on the rope at a rate of .5 seconds a ya

rd, how long will it take them to reach the tree house?
Mathematics
1 answer:
mezya [45]3 years ago
4 0

Answer:

Time = 250

Step-by-step explanation:

Given

Length = 500yd

Rate = 0.5sec/yd

Required

Determine the time taken to reach the house

The given rate is a ratio of time to length.

i.e.

Rate = \frac{Time}{Length}

Make Time the subject

Time = Rate * Length

Substitute values for Rate and Length

Time = 0.5 * 500

Time = 250

<em>Hence, the time taken is 250 seconds</em>

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Find the value of x so that L is parallel to M. State the converse used!
galben [10]

Answer:

<h3>6 degrees</h3>

Step-by-step explanation

Find the diagram attached. In Line geometry, there is a theorem that states that the sum of the adjacent interior angles is 180 degrees. According to the diagram, the adjacent interior angles are 7x- 15 and 24x + 9.

The sum of this angles must give 180 degrees as shown;

7x-15 + 24x + 9 = 180

7x+24x-15+9 = 180

31x-6 = 180

31x = 180+6

31x = 186

x = 186/31

x = 6

Hence the value of x is 6 degrees

3 0
2 years ago
PLEASE HELP ASAP!!
Sunny_sXe [5.5K]
Y=50+.05x

Just plug in the number of texts for x

y=50+.05(25)
y=51.25

^That was for 25 texts

Now just plug in all the other texts and replace that with x

Hope this helps!
4 0
3 years ago
A factory worker productivity is normally distributed. one worker produces an average of 75 units per day with a standard deviat
Angelina_Jolie [31]
Let Xi be the random variable representing the number of units the first worker produces in day i.
Define X = X1 + X2 + X3 + X4 + X5 as the random variable representing the number of units the
first worker produces during the entire week. It is easy to prove that X is normally distributed with mean µx = 5·75 = 375 and standard deviation σx = 20√5.
Similarly, define random variables Y1, Y2,...,Y5 representing the number of units produces by
the second worker during each of the five days and define Y = Y1 + Y2 + Y3 + Y4 + Y5. Again, Y is normally distributed with mean µy = 5·65 = 325 and standard deviation σy = 25√5. Of course, we assume that X and Y are independent. The problem asks for P(X > Y ) or in other words for P(X −Y > 0). It is a quite surprising fact that the random variable U = X−Y , the difference between X and Y , is also normally distributed with mean µU = µx−µy = 375−325 = 50 and standard deviation σU, where σ2 U = σ2 x+σ2 y = 400·5+625·5 = 1025·5 = 5125. It follows that σU = √5125. A reference to the above fact can be found online at http://mathworld.wolfram.com/NormalDifferenceDistribution.html.
Now everything reduces to finding P(U > 0) P(U > 0) = P(U −50 √5125 > − 50 √5125)≈ P(Z > −0.69843) ≈ 0.757546   .
5 0
3 years ago
A set of four postcards costs $1.00. Single postcards cost $0.50. What is the least amount of money you
shepuryov [24]

Answer: 3 Sets of the 4 post cards and 3 of the single post cart sets.

Step-by-step explanation:

You buy 3 of the 4 post card set becuase that is the most you can get of those to get under 15 post cards.

You would now have 12 postcards now you have to buy 3 of the single set to get to 15 cards

3 0
3 years ago
Read 2 more answers
Order from least to greatest
Dafna1 [17]
3.75, 3.9, 4.256, 4.258, 4.5
3 0
4 years ago
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