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2 years ago

Can someone help me with this one, please

Mathematics

1 answer:

Gala2k [10]2 years ago

7 0

Answer:

<h2>Sorry I couldn't find it.</h2>

Step-by-step explanation:

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Solve 5x(x-6)(4x+9)=0

xxTIMURxx [149]

Greetings and Happy Holidays!

Solve for x.
$5x(x-6)(4x+9)=0$ <span>

Distribute the parenthesis:
</span> $5x(x-6)(4x+9)=0$

$(5x^2-30x)(4x+9)=0$

$(20x^3-120x^2)+(45x^2-270x)=0$

Combine like terms:
$20x^3-75x^2-270x=0$

Factor out GCF (5x):
$5x(4x^2-15x-54)=0$

Factor the Complex Trinomial:
$5x(4x^2+9x-24x-54)=0$

$5x(x(4x+9)-6(4x-9))=0$

$5x((4x+9)(x-6))=0$

Set Factors to Equal 0:
$5x=0$

$x=0$

or

$4x+9=0$

$4x=-9$

$x=\frac{-9}{4}$

or

$x-6=0$

$x=6$

The Answers Are:
$\boxed{x=0} \\ \boxed{x= \frac{-9}{4}} \\ \boxed{x=6}$

I hope this helped!
-Benjamin

8 0

2 years ago

An art class is making a mural for the school that has a triangle drawn in the middle. The length of the bottom of the triangle

Arte-miy333 [17]

Answer:

Step-by-step explanation:

4 0

2 years ago

Which postulate or theorem proves that these two triangles are

melamori03 [73]

Answer: AAS

Step-by-step explanation:

3 0

2 years ago

The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago

A circle cuts the x-axis at (4,0) and (14,0), and cuts the y-axis at (0,6) and (0,8). Find it's equation

gayaneshka [121]

It is not a circle but you can find the equation of the ellipse.
To do this we need to work out the major and minor radii and the centre
The centre is at (9, 7)
The major (y) radius is 1 and the minor (x) radius is 5
Therefore the equation is (x-9)/5 + (y-7)/1 = 1

5 0

3 years ago