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2 years ago

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Pedro has a bag with 8 yellow marbles, 9 blue marbles, 12 green marbles, and 7 red marbles. What is the probability that Pedro w

ill pull out a yellow or red marble?

2 answers:

Anna71 [15]2 years ago

6 0

Answer:

This is the answer of your question. ☺☺

Shalnov [3]2 years ago

5 0

Step-by-step explanation:

15/36 = 41.6%

because there are 36 total marbles. and 15 of them are either red or yellow.

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WORTH 20 POINTS IF CORRECT! Write the slope-intercept form of the equation of each line show or explain your work. 1. is (0,4) (

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Answer:

1. y=5/2x+4

2. y=-7x-3

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Step-by-step explanation:

You have to add it in the slope intercept formula

2. M=-7 and B=-3

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Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.

Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

$y=ax^2+bx+c$

Here the vertex of an up - down facing parabola has a form of,

$x_v=-\dfrac{b}{2a}$

The parameters we have are,

$a=-5,b=-10, c=6$

Plug them in vertex formula,

$x_v=-\dfrac{-10}{2(-5)}=-1$

Plug in the $x_v$ into the equation,

$y_v=-5(-1)^2-10(-1)+6=11$

We now got a point parabola vertex with coordinates,

$(x_v, y_v)\Longrightarrow(-1,11)$

From here we emerge two rules:

If $a$ then vertex is max value
If $a>0$ then vertex is min value

So our vertex is minimum value since,

$a=-5\Longleftrightarrow a$

Hope this helps.

r3t40

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2 years ago

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating <em>11 units to the left:</em>

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating<em> 5 units down:</em>

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ <em>must be</em> less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.

<em>Therefore, the right answer is </em><em>b. f(x) = 1/2(x + 11)^2 - 5</em>

SECOND.

Translating <em>8 units to the right:</em>

$g(x)=f(x-8) \\ \\ \therefore g(x)=(x-8)^2$

Then translating<em> 1 unit down:</em>

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x-8)^2-1$

As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.

<em>Therefore, the right answer is </em><em>a. g(x) = 1/3(x - 8)^2 - 1</em>

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3 years ago