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bagirrra123 [75]
2 years ago
12

Which polynomial function could be represented by the graph below?

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
5 0

Answer:

Option B: f(x) = 2x2 + 2x – 4

Step-by-step explanation:

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Step-by-step explanation:

To answer this question, we need to that any number (except zero) raised to power 0 is equal to 1. With that in mind, let's solve this:

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<em>N</em><em>o</em><em>t</em><em>e</em><em>:</em><em> </em><em>2</em><em>y</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>y</em><em>^</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>1</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>w</em><em>h</em><em>e</em><em>r</em><em>e</em><em>a</em><em>s</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>2</em><em>y</em><em>)</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>1</em>

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\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}&#10;\\\\\\&#10;f(x)=x+1\qquad \qquad \qquad  \qquad  \qquad  g(x)=x+1\\\\&#10;-------------------------------\\\\&#10;\textit{they're, kinda, except that, when x = 1}&#10;\\\\\\&#10;g(x)=(1)+1\implies g(x)=2&#10;\\\\\\&#10;f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined
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