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goblinko [34]
2 years ago
9

Angle marked 7x + 4 as degree

Mathematics
2 answers:
VladimirAG [237]2 years ago
8 0
Your answer would be: 1

Happy holidays and hope this helps!
Andrei [34K]2 years ago
5 0
The answer would be one
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Derek is hang gliding on a clear day at an altitude of a feet. His visibility, v, is 67.1 mi. Use the formula v = 1.225 to find
Margaret [11]

Base on the visibility formula v = 1.225√a, the altitude at which Dereck is hang gliding is 7.4 miles

<h3>How to find altitude using visibility formula?</h3>

The visibility formula is given as follows:

v = 1.225√a

where

  • a = altitude
  • v = visibility

Therefore,

v = 67.1 miles

v = 1.225√a

67.1 = 1.225√a

divide both sides by 1.225

√a = 67.1 / 1.225

√a = 54.7755102041

square both sides

√a² = √54.7755102041

a = 7.40104789878

a = 7.4 miles

learn more on visibility here: brainly.com/question/16166215

6 0
2 years ago
Read 2 more answers
⚠️Attention ⚠️HELPPPPPP!!!!!
german

Answer:

it would be B.

Step-by-step explanation:

6 0
3 years ago
How do you completely factor:<br><br> 2x^3 – 5x^2 – 22x + 55
DochEvi [55]

Answer:(X^2-11)(2X-5)

Step-by-step explanation:

2x^3-5x^2-22x+55

x^2(2x-5)-11(2x-5)

(X^2-11)(2X-5)

8 0
3 years ago
In preparing a certain ointment, a pharmacist used 28.35 g of zinc oxide instead of the 31.1 g called for. Calculate the percent
Vilka [71]

Answer: 9.70%

Step-by-step explanation:

The formula to find the percentage error is given by :-

\%\text{ error}=\dfrac{|\text{Estimate-Actual}|}{\text{Actual}}\times100

Given : Actual mass of zinc oxide used by pharmacist = 28.35 g

Estimated mass of zinc oxide used by pharmacist =31.1 g

Now, \%\text{ error}=\dfrac{|31.1-28.35|}{28.35}\times100

i.e. \%\text{ error}=\dfrac{2.75}{28.35}\times100

i.e. \%\text{ error}=9.70017636684\approx9.70\%

Hence, the  percentage of error on the basis of the desired quantity.= 9.70%

5 0
3 years ago
Quadrilateral PQRS is inscribed in a circle , as shown. Which statement is true?
AveGali [126]

Answer: C

Step-by-step explanation:

6 0
3 years ago
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