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Effectus [21]
3 years ago
14

Marianna is painting a ramp for the school play in the shape of a right triangular prism. The ramp has dimensions as shown below

. She will not paint the back or bottom surfaces of the ramp. What is the surface area of the ramp?
Just include the front and sides of the ramp.

A
4 square inches

B
300 square inches

C
2,905 square inches

D
3,672 square inches

Mathematics
2 answers:
Andru [333]3 years ago
8 0

Answer:

..

Step-by-step explanation:

..

Dmitriy789 [7]3 years ago
4 0

Answer: The correct answer will be 4

Step-by-step explanation:

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X=<br> Length=<br> Width=<br> WILL GIVE BRAINLIEST + 5 star
babymother [125]

Answer:

x = 20

Length = 20ft

Width = 12ft

Step-by-step explanation:

A = 240

x^2 - 8x = 240

x^2 - 8x - 240 = 0

x^2 - 20x + 12x - 240 = 0

x(x-20) + 12(x-20) = 0

(x+12)(x-20) = 0

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x = -12 (which we discard since x is a length)

So the dimensions are 20ft and 20-8 = 12ft

7 0
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Marizza181 [45]

9514 1404 393

Answer:

  ∠Q = 89°

  ∠R = 123°

  ∠S = 91°

Step-by-step explanation:

It seems easiest to start by finding the measures of each of the arcs. The measure of an arc is double the measure of the inscribed angle it subtends.

  arc QRS = 2·∠P = 114°

So, ...

  arc QR = arc QRS - arc RS = 114° -41° = 73°

The total of the arcs around the circle is 360°, so ...

  arc PQ = 360° -arc PS -arc QRS

  arc PQ = 360° -137° -114° = 109°

__

  ∠Q = (1/2)(arc RS + arc PS) = (1/2)(41° +137°)

  ∠Q = 89°

__

  ∠R = (1/2)(arc PS +arc PQ) = (1/2)(137° +109°)

  ∠R = 123°

__

  ∠S = (1/2)(arc PQ +arc QR) = (1/2)(109° +73°)

  ∠S = 91°

7 0
3 years ago
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Answer:

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