Answer:
( 1 = sin² + cos²)
Step-by-step explanation:
Answer:
y=-3x+50
Step-by-step explanation:
y=50-3x ,where x is number of days.
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
__
You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
__
Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Answer:
A) x-3 and D) x+9
Step-by-step explanation:
x^2 + 6x - 27
You need to find two numbers that multiply to -27 and add up to 6
Those two numbers are -3 and 9, because 9 * -3 = -27 and 9+ -3 = 6
So you add those to x and those are your two factored binomials
(x-3) and (x+9)
Answer:
to the third power ?
Step-by-step explanation:
