Answer:
34 minutes
Step-by-step explanation:
Given
Required
Number of minutes left to spend (x)
Since there's only 1 minute left to spend on every other call;
Time left = x * 1
Time left = x
The required can further be calculated using:
This gives:
Subtract 6 from both sides
<em>Hence, there are 34 minutes left to spend</em>
Yes because it has 0 in it
9x^2 + 18x + 9 = 5
9(x^2 + 2x +1) - 5 = 0
x^2 + 2x - 4 = 0
Then use the quadratic formula.
542 beacuse 142+400
4+1=5 4+0=a 2+0=2
Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614
