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mina [271]
3 years ago
9

The melting points of four impure samples of lead(II) bromide were measured. The results are

Chemistry
1 answer:
CaHeK987 [17]3 years ago
4 0

Answer:

D

372

373

Explanation:

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When the equal molar amounts of of both the acid and the base were reacts, what happened in the reaction?
Advocard [28]
It is going to be reaction of neutralization, and water and salt will be formed. If acid and base are strong, the reaction of the solution should become neutral.
3 0
3 years ago
Le Chatelier's Principle. For the reaction below, if the equilibrium concentrations were NH3 = 2 x 10-4, H3O+ = 2 x 10-4M and NH
telo118 [61]

Answer:

Explanation:

NH3 + H3O+ --> NH4+ + H2O

equllibrium constant =K = [ H2O] [NH4+] / [NH3] [H3O+ ]

                                      =

by inserting thier respecive values can you calcaulte, by the way coniseder  [ H2O] =1 ,

6 0
3 years ago
A 7.2 L balloon at 2 atm of pressure has its pressure reduced to 0.5 atm. What is the new size of the balloon, in liters?
alexgriva [62]

Explanation:

using Boyles law: which shows the relationship between pressure and volume, when temperature Is kept constant

P1V1 = P2V2

2 x 7.2 = 0.5 x V2

14.4 = 0.5 x V2

V2 = 14.4/0.5 = 28.8 L

Hence the new size of the balloon in litres is 28.8

8 0
3 years ago
Need to complete the chart
GalinKa [24]

Answer:

Row 1

[H^+]=1.8\times 10^{-6}M

pH=-\log[H^+]=-\log[1.8\times 10^{-6}]=5.7

pOh=14-pH=14-5.7=8.3

pOH=-\log[OH^-]

[OH^-]=0.5\times 10^{-8}M

Hence, acidic

Row 2

[OH^-]=3.6\times 10^{-10}M

pOH=-\log[OH^-]=-\log[3.6\times 10^{-10}]=9.4

pH=14-pOH=14 - 9.4 = 4.6

pH=-\log[H^+]

[H^+]=2.6\times 10^{-5}M

Hence, acidic

Row 3

pH = 8.15

[H^+]=0.7\times 10^{-8}M

pOH=14-pH=14 - 8.15 = 5.8

pOH=-\log[OH^-]

[OH^-]=1.5\times 10^{-6}M

Hence, basic

Row 4

pOH = 5.70

[OH^-]=1.8\times 10^{-6}M

pH=14-pOH=14 - 5.70 = 8.3

pH=-\log[H^+]

[H^+]=0.5\times 10^{-8}M

Hence, basic



3 0
3 years ago
What type of compound does the formula, CuCl2, represent?<br> a. ionic salt<br> b. covalent molecule
Rainbow [258]
The answer is:  [B]:  "ionic salt" .
___________________________________________________
Note:  There is no "sharing of electrons" among the elements in this compound; so this compound in NOT a "covalent molecule".

However, there is ionic bonding:  Cu²⁺ and  Cl⁻  ;  to form:  "CuCl₂" .
____________________________________________________ 
7 0
3 years ago
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