All categories

3 years ago

What is the slope of the line perpendicular to the line that passes through (4,7) and (8,9)?

Mathematics

2 answers:

melamori03 [73]3 years ago

5 0

Answer:

-2

Step-by-step explanation:

the line that passes trough (4, 7) and (8, 9) has the slope

m= (y2-y1)/ (x2-x1) = 7-9 / 4-8 = -2/ -4 = 1/2

perpendicular lines have their slope negative reciprocal

m= -2 is the slope of the perpendicular line that goes trough the given points

Strike441 [17]3 years ago

4 0

Ima try and find it for you

You might be interested in

Click on the picture to look at some equivalent fractions. Look at them closely. Can you see a relationship of any kind between

Vera_Pavlovna [14]

when you simplify 2/4 it equals 1/2. Making them both equal the same.

2/3 when you double the numbers to make a bigger fraction you make 4/6.

2x2 = 4/ 3x3= /6 = 4/6

3/9 simplified is 1/3. Three goes into three one time, making the top one and three goes into 9 three times making the bottom 3.

When 9/12 is rounded down it is equivalent to 3/4

5 0

3 years ago

Read 2 more answers

Two thirds equals 18 over x plus 5

Wewaii [24]

Problem: 2/3= 18/(x+5)

First, I would multiply the (x+5) over

Making it 2/3(x+5)=18

Second, I would Divide by 2/3 (which is the same as multiplying by the reciprocal 3/2)

which shows up like this now (x+5)=18*3/2

third I would subtract the 5 over

which will give you your answer

7 0

3 years ago

Look at the formula for the volume of a cylinder below.

scZoUnD [109]

$h = V / ( \pi r^2)$

Okay, so we already have the volume equation for a cylinder here.
$V = \pi r^2 h$
Since we need to find the height(h), we need to basically isolate it in the equation. To do that we just have to divide both sides by (pi * r^2), where we end up with:
$V / (\pi r^2) = h(\pi r^2) / (\pi r^2)$
then
$V / ( \pi r^2) = h$
$h = V / ( \pi r^2)$

8 0

3 years ago

20 points!! Solve this system of lineal equations.separate the x- and y- values with a comma

Zielflug [23.3K]

Solve the following system:{12 x = 54 - 6 y | (equation 1)-17 x = -6 y - 62 | (equation 2)
Express the system in standard form:{12 x + 6 y = 54 | (equation 1)-(17 x) + 6 y = -62 | (equation 2)
Swap equation 1 with equation 2:{-(17 x) + 6 y = -62 | (equation 1)12 x + 6 y = 54 | (equation 2)
Add 12/17 × (equation 1) to equation 2:{-(17 x) + 6 y = -62 | (equation 1)0 x+(174 y)/17 = 174/17 | (equation 2)
Multiply equation 2 by 17/174:{-(17 x) + 6 y = -62 | (equation 1)0 x+y = 1 | (equation 2)
Subtract 6 × (equation 2) from equation 1:{-(17 x)+0 y = -68 | (equation 1)0 x+y = 1 | (equation 2)
Divide equation 1 by -17:{x+0 y = 4 | (equation 1)0 x+y = 1 | (equation 2)
Collect results:Answer: {x = 4 {y = 1

Please note the { are supposed to span over both equations but it interfaces doesn't allow it. Please see attachment for clarification.

7 0

3 years ago

Please HELP I NEED HELPPPPPPPPPPPPP Natasha is constructing the bisector of PQ¯¯¯¯¯. She has already constructed an arc as shown

Korvikt [17]

C is your correct answer

6 0

3 years ago