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3 years ago

What is the slope of the line perpendicular to the line that passes through (4,7) and (8,9)?

Mathematics

2 answers:

melamori03 [73]3 years ago

5 0

Answer:

-2

Step-by-step explanation:

the line that passes trough (4, 7) and (8, 9) has the slope

m= (y2-y1)/ (x2-x1) = 7-9 / 4-8 = -2/ -4 = 1/2

perpendicular lines have their slope negative reciprocal

m= -2 is the slope of the perpendicular line that goes trough the given points

Strike441 [17]3 years ago

4 0

Ima try and find it for you

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Brainiest to whoever correct

dolphi86 [110]

74-34=20 so then y=20 because 20*2+34=74

IN other words

74-34=20

7 0

3 years ago

If the top of a 4.50 m ladder reaches twice as far up a vertical wall as the foot of the

STALIN [3.7K]

Answer:

4 m.

Step-by-step explanation:

Length of ladder, L = 4.50 m

Base of ladder from the wall, B = x

Height of the wall, H = 2x

Using Pythagoras theorem

$L^2 = B^2 + H^2$

$4.5^2 = x^2 + (2x)^2$

$5x^2 = 4.5^2$

$x = 2\ m\ (approx.)$

Height of the wall is equal to 2 x 2 = 4 m.

6 0

4 years ago

Find the solution of the given initial value problem. ty' + 6y = t2 − t + 1, y(1) = 1 6 , t > 0

gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

$ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0$

Divide this by t to get in linear form

$y'+6y/t = t-1+1/t$

This is of the form

y' +p(t) y = Q(t)

where p(t) = 1/t $e^(\int 1/tdt) = t$

So solution would be

$yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C$

siubstitute y(1) = 16

$16 = 16^3/3-128+1+C\\C = -1206$

4 0

3 years ago

A square has a length of 4.8 feet. If the square is dilated by a factor of 4 , what is the length of a side of the new square? W

oksano4ka [1.4K]

Answer:

4.8x4=19.2, and then 19.2/4=4.8 feet

Each side would be 4.8 feet

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3 years ago

I WILL MARK AS BRAINLIEST!!! What is the value of x?<br><br> 8x+3=43

uysha [10]

8x+3=43
-3 -3
8x=40
/8 /8
X=5

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3 years ago