Answer:
The graph is attached.
Step-by-step explanation:
The range of this data is the highest value, 22, subtracted by the lowest value, 1: 22-1 = 21.
Using boundaries, the first bar would go from 0.5-3.5; the second from 3.5-6.5; the third from 6.5-9.5; the fourth from 9.5-12.5; the fifth from 12.5-15.5; the sixth from 15.5-18.5; the seventh from 18.5-21.5; and the eighth from 21.5-24.5.
The frequency of the first bar, its height, would be 1; the height of the second bar is 2; the height of the third bar is 3; the height of the fourth bar is 2; the height of the fifth bar is 3; the height of the sixth bar is 1; the height of the seventh bar is 1; and the height of the eighth bar is 1.
Answer:
A. 23+(6-1)x-3
B. 93
Step-by-step explanation:
a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference
6th row = 23 + (6 - 1) x -3
= 23 + (5) x -3
= 23 + (-15)
= 8 - number of boxes in the top row.
b) Sum = N/2[2F + (N - 1) x D]
= 6/2[2*23 + (6 - 1) x -3]
= 3 [46 + (5) x -3 ]
= 3 [46 + -15 ]
= 3 [ 31 ]
= 93 - total number of boxes in the entire display.
Hope this helps! Its 3:25 AM for me too so I know how you feel.
The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign
4 + 6 = 10
10/2 = 5
Add 5 to -4
5 + -4 = 1
H is your midpoint
True. As long as AB and BC are on the same line, AB + BC = AC
hope this helps
Answer:
dont know sry
Step-by-step explanation:
Answer:
1 student.
Step-by-step explanation:
Two thirds of the students preferred chocolate ice cream:
2/3 of 36 is 24 students.
One fourth of the students preferred strawberry ice cream:
1/4 of 36 is 9.
9+24= 35
<em>--------------------------------------------------------------------------------------</em>
36-35=1
Only one student preferred vanilla ice-cream.
